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LynFran
 one year ago
please help me prove this identity im stuck not geting it out at all!
(1+tanx+cotx)(cosxsinx)=(cscx/sec^2x secx/csc^2x)
LynFran
 one year ago
please help me prove this identity im stuck not geting it out at all! (1+tanx+cotx)(cosxsinx)=(cscx/sec^2x secx/csc^2x)

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Loser66
 one year ago
Best ResponseYou've already chosen the best response.1just distribute the left hand side, you can get the right hand side.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1im ending up with \[(\sin^2x/cosx+\cos^2x/sinx)\] when i distribute it

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1or \(\dfrac{cos^2}{sin}\dfrac{sin^2}{cos}\) right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1now, \(sin = \dfrac{1}{csc}\) hence \(csc = \dfrac{1}{sin}\) right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1and \(sec (x) =\dfrac{1}{cos(x)} \rightarrow cos(x) =\dfrac{1}{sec(x)}\)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1hence the first term is \(\dfrac{csc (x)}{sec^2(x)}\) do the same with the second term. combine to get the right hand side
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