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anonymous

  • one year ago

thanks

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  1. Loser66
    • one year ago
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    sin^2 = 1- cos ^2 ok? replace and let the terms all in left hand side , the right hand side =0. Show me that step, please

  2. Loser66
    • one year ago
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    Do you know how to solve quadratic ?

  3. anonymous
    • one year ago
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    no.....

  4. Loser66
    • one year ago
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    But we have no way to find out the solution without quadratic. How can I help??

  5. anonymous
    • one year ago
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    a =pi

  6. Loser66
    • one year ago
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    @cutegirl I shouldn't give you a free answer because it doesn't help you on long run.

  7. anonymous
    • one year ago
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    got it

  8. Loser66
    • one year ago
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    3cos a +3 = 1 - cos^2 a cos^2a +3cosa +2=0 (cos a+2) (cos a +1) =0 cos a +2 never =0 , because it is out of range hence , just cos a +1 =0 , then cos a =-1, hence a = pi + 2kpi.

  9. Loser66
    • one year ago
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    yup. if limit is given, like from 0 to 2pi, then the answer is a =pi if you don't have any limit, then a = pi +2kpi

  10. anonymous
    • one year ago
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    thanks so much !!!!

  11. Loser66
    • one year ago
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    I don't know, you must look at your problem (the paper) , it is not up to me.

  12. anonymous
    • one year ago
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    ow i c thanks

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spraguer (Moderator)
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