anonymous
  • anonymous
Solve the equation by completing the square. 6x^2-x-5=0 So far i got x^2-1/6x-5/6=0 x^2-1/6x=5/6 Now i dont understand this step by add the square of half of -1/6 to both sides I dont understand what that means please help
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
why?....
pooja195
  • pooja195
Cant we just factor it?
anonymous
  • anonymous
okay

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pooja195
  • pooja195
anonymous
  • anonymous
@pooja195 i have the steps and it says add the square of half of -1/6 to both sides but i dont understand how that answer is 1/144
pooja195
  • pooja195
hmm im not sure how to do it that way @Loser66 might know :3
anonymous
  • anonymous
This is what it says by the way http://prntscr.com/7dnq4a
Loser66
  • Loser66
you are good until \(x^2 -(1/6)x -(5/6)=0\) Now, I pick the middle term to say, ok? to have a complete the square, you have formula \((x-a)^2 = x^2 -2ax+a^2\) right? your middle term is (1/6) x, right?
Loser66
  • Loser66
so, to find a, the term we need to have the complete square, I do \(2a x = \dfrac{1}{6}x\), hence \(2a=\dfrac{1}{6}\), so \(a =\dfrac{1}{12}\) so far so good?
anonymous
  • anonymous
erm erm @Loser66 ok like what you saying sounds good lol but like i have to follow this way :S did you see the picture i posted ? http://prntscr.com/7dnq4a
Loser66
  • Loser66
Now, the original one \(x^2 -2 (\dfrac{1}{12}) x +\color{red}{(\dfrac{1}{12})^2} - \color{red}{(\dfrac{1}{12})^2}-\dfrac{5}{6}=0\)
Loser66
  • Loser66
@Tyler1204 it is not "sounds good". I explained you why 1/144 appears.
anonymous
  • anonymous
OH OH erm ok let me re read then lol sorry
Loser66
  • Loser66
You killed my feeling.
anonymous
  • anonymous
Grrr im still confused because for me it dos not say anything about that formula you said :/ (x-a)^2=x^2-2ax+a^2 Did you open the picture? because like i have to follow what it says :S
anonymous
  • anonymous

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