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Jravenv

  • one year ago

Help me with this?

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  1. Jravenv
    • one year ago
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  2. sdfgsdfgs
    • one year ago
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    can u start by multiplying left and right hand side by 3? what will u get?

  3. Jravenv
    • one year ago
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    9

  4. Jravenv
    • one year ago
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    and I don't know who to do the other :/

  5. sdfgsdfgs
    • one year ago
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    Relax and let's work on it together okay? \[a = \frac{ x + y + z }{ 3 }\] multiplying left and right hand side by 3 - what will u get?

  6. Jravenv
    • one year ago
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    Okay thanks, 3a+ x+y+z?

  7. sdfgsdfgs
    • one year ago
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    Almost...it should be: 3a = x + y + z u mixed up the "=" and "+" sign but its okay!

  8. Jravenv
    • one year ago
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    Oh /.\ sorry! What do I do next?

  9. sdfgsdfgs
    • one year ago
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    subtract 3a from the left and right, now what u get?

  10. Jravenv
    • one year ago
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    Um x+y+z-3a?

  11. sdfgsdfgs
    • one year ago
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    correct on the right hand side of the = sign....but how about the left hand side?

  12. Jravenv
    • one year ago
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    -3a=x+y+z-3a?

  13. sdfgsdfgs
    • one year ago
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    The right hand side was 3a before...now subtracting 3a from that, what will u get?

  14. Jravenv
    • one year ago
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    0!

  15. sdfgsdfgs
    • one year ago
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    Good job :) so we have 0 = x + y + z - 3a Now plz look at the choices in ur Q, what do u see?

  16. Jravenv
    • one year ago
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  17. anonymous
    • one year ago
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    not to butt in but your job is to solve for \(y\) not to set it equal to zero it takes two steps only

  18. sdfgsdfgs
    • one year ago
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    so y is by itself on one side right? that means u need to move everything else on the other side...

  19. sdfgsdfgs
    • one year ago
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    @satellite73 yes, sorry I realize...too late...that I should have kept 3a on the left....

  20. Jravenv
    • one year ago
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    What do I do then?

  21. sdfgsdfgs
    • one year ago
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    take a step back... 3a = x + y + z now because as @satellite73 said, we need to solve for y. So we need to move x and z over to the left hand side. ok?

  22. Jravenv
    • one year ago
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    Okay

  23. sdfgsdfgs
    • one year ago
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    We do that by subtracting x + y from the left and right hand side of the = sign what will be on the left?

  24. Jravenv
    • one year ago
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    3a- x+y= z?

  25. sdfgsdfgs
    • one year ago
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    Yes and I made a mistake again :(

  26. sdfgsdfgs
    • one year ago
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    So it should look like this.... 3a - (x+z) = x + y + z - (x+z) so far so good?

  27. Jravenv
    • one year ago
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    I think I figured it out, is it this? y = 3a - x - z

  28. sdfgsdfgs
    • one year ago
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    Bingo :) u got it!

  29. Jravenv
    • one year ago
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    THANKS! YAY!

  30. sdfgsdfgs
    • one year ago
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    welcome!

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