## Jravenv one year ago Help me with this?

1. Jravenv

2. sdfgsdfgs

can u start by multiplying left and right hand side by 3? what will u get?

3. Jravenv

9

4. Jravenv

and I don't know who to do the other :/

5. sdfgsdfgs

Relax and let's work on it together okay? $a = \frac{ x + y + z }{ 3 }$ multiplying left and right hand side by 3 - what will u get?

6. Jravenv

Okay thanks, 3a+ x+y+z?

7. sdfgsdfgs

Almost...it should be: 3a = x + y + z u mixed up the "=" and "+" sign but its okay!

8. Jravenv

Oh /.\ sorry! What do I do next?

9. sdfgsdfgs

subtract 3a from the left and right, now what u get?

10. Jravenv

Um x+y+z-3a?

11. sdfgsdfgs

correct on the right hand side of the = sign....but how about the left hand side?

12. Jravenv

-3a=x+y+z-3a?

13. sdfgsdfgs

The right hand side was 3a before...now subtracting 3a from that, what will u get?

14. Jravenv

0!

15. sdfgsdfgs

Good job :) so we have 0 = x + y + z - 3a Now plz look at the choices in ur Q, what do u see?

16. Jravenv

17. anonymous

not to butt in but your job is to solve for $$y$$ not to set it equal to zero it takes two steps only

18. sdfgsdfgs

so y is by itself on one side right? that means u need to move everything else on the other side...

19. sdfgsdfgs

@satellite73 yes, sorry I realize...too late...that I should have kept 3a on the left....

20. Jravenv

What do I do then?

21. sdfgsdfgs

take a step back... 3a = x + y + z now because as @satellite73 said, we need to solve for y. So we need to move x and z over to the left hand side. ok?

22. Jravenv

Okay

23. sdfgsdfgs

We do that by subtracting x + y from the left and right hand side of the = sign what will be on the left?

24. Jravenv

3a- x+y= z?

25. sdfgsdfgs

Yes and I made a mistake again :(

26. sdfgsdfgs

So it should look like this.... 3a - (x+z) = x + y + z - (x+z) so far so good?

27. Jravenv

I think I figured it out, is it this? y = 3a - x - z

28. sdfgsdfgs

Bingo :) u got it!

29. Jravenv

THANKS! YAY!

30. sdfgsdfgs

welcome!