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anonymous

  • one year ago

Which statement is true about the product square root of 2(3square root of 2 + square root of 14)? It is rational and equal to 12. It is rational and equal to 18. It is irrational and equal to 6 + 2square root of 18. It is irrational and equal to 3 +square root of 18.

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  1. geerky42
    • one year ago
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    \[\sqrt{2}(3\sqrt2 + \sqrt{14})\]Right? What do you think so far?

  2. geerky42
    • one year ago
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    You can split \(\sqrt{14}\) into two square roots; \(\sqrt{14} = \sqrt{2\cdot7}=\sqrt2\sqrt7\)

  3. geerky42
    • one year ago
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    \[\sqrt{2}(3\sqrt2 + \sqrt2\sqrt7)\] Now distribute \(\sqrt2\)

  4. anonymous
    • one year ago
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    Um I think I get it but what next?

  5. anonymous
    • one year ago
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    simplifying further, you'll get \[6+2\sqrt{7}\]

  6. anonymous
    • one year ago
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    so would that be c ? @aryandecoolest

  7. anonymous
    • one year ago
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    @geerky42

  8. anonymous
    • one year ago
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    C

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