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anonymous
 one year ago
thanks
anonymous
 one year ago
thanks

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are going to want to use a double angle identity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you still remember you Double angle formulas?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you don't you can quickly find them on the net with a quick search :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From there, it is usually trial and error to see what you get in the end, how would you start this one off ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use a double angle formula for the left side and convert the right side in terms of sin and cos

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So straight away we can change Sin(2x) into 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02cos(2x)/sin(2x)= 2sinxcosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No just Sin(2x) = 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The Cos(2x) is something we have to play around with, since there are three variants of this particular double angle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ummm... I not entirely sure how you got that ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In this question we are proving that LHS = RHS not finding a value for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ow got it so what are we doing next

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, I'll show you what I got, and lets work from there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0= 2Cos(2x) Sin2(x) = 2[1sin^2x] 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that final answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not even haha, its just the first step ^^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So from there > Expand inwards 2  2Sin^2x 2SinxCox

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No split the fraction into: 2  2Sin^2x 2SinxCosx 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Firstly we'll solve this part first: 2 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0From here, we can clearly cancel the two's out ^^ So it will become 1 SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you say to your self, how do we get tanx? out of 1 SinxCosx well remember that sinx / cosx = tanx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Be careful. You can't get tan out of 1/sinxcosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We have to move the Sinx into the numerator, by taking the reciprocal of that. Note that the reciprocal is different from inverse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just like this mate, (Sinx)^1 Cos (Tanx)^1 = Tan^1x > Apply the inverse of Tan to get Cot Cotx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I meant, the reciprocal of tan to get cot ><

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now we have to fine the other part, which is straight forwards stuff :) 2Sin^2x 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we have to get Tanx out of 2Sin^2x 2SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would you approach in doing this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0get rid of two 2sin and be left with xcosx?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if only XD But your procedure is a bit off >< I'll show you :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we can cancel out the two's to get 2Sin^2x = Sin^2x 2SinxCosx SinxCosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because the two's are just coefficients in front of the terms, they don't act like terms themselves :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyways, from there notice how Sin^2x has a power of 2 That means Sinx . Sinx = Sin^2x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So by working out we get Sinx . sinx Sinx Cosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We can easily cancel the Sinx / sinx to get 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And finally <Drums> 1 . Sinx = Tanx Cosx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And so we have proven that 2cos(2x)/sin(2x)=cot(x)tan(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah just remember that Sinx/cosx = tanx :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much!!!!!!!!!!!!!!!!!!!!!!!
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