AmTran_Bus
  • AmTran_Bus
Please help me solve for k!
Mathematics
chestercat
  • chestercat
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AmTran_Bus
  • AmTran_Bus
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AmTran_Bus
  • AmTran_Bus
The book says k= 1/10 ln 3040/2560 But where did that come from?
AmTran_Bus
  • AmTran_Bus
Is it just a plain ration between t and, well, k?

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zepdrix
  • zepdrix
\[\Large\rm y(10)=2560e^{10k}=3040\]Apply log, then log rule :)
zepdrix
  • zepdrix
Err divide first, woops,\[\Large\rm \frac{3040}{2560}=e^{10k}\]
zepdrix
  • zepdrix
Log each side,\[\Large\rm \ln\left(\frac{3040}{2560}\right)=\ln\left(e^{10k}\right)\]
zepdrix
  • zepdrix
log rule,\[\Large\rm \ln\left(\frac{3040}{2560}\right)=10k\ln\left(e\right)\]Then uh, simplify...\[\Large\rm \ln\left(\frac{3040}{2560}\right)=10k\cdot 1\]ya?
AmTran_Bus
  • AmTran_Bus
Yes. That is making some sense. So then, you have .178=10k
zepdrix
  • zepdrix
.1719* woops i think u missed a decimal value there.
AmTran_Bus
  • AmTran_Bus
My bad! So, what do you do with the 10k?
zepdrix
  • zepdrix
solve for k 0_o 10 is multiplying the k, ya? do the inverse of multiplication to isolate your k
AmTran_Bus
  • AmTran_Bus
I mean, it is set equal to it as is, but dont you plug it into k?
AmTran_Bus
  • AmTran_Bus
Oh, your post above, sorry!
AmTran_Bus
  • AmTran_Bus
.01719
AmTran_Bus
  • AmTran_Bus
James Stewart wrote some of these examples confusing!
zepdrix
  • zepdrix
hehe
AmTran_Bus
  • AmTran_Bus
Thank you.
zepdrix
  • zepdrix
no probsss

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