given the sin a=-2/3 and a is in quadrant what are the exact values of the following trigonometric functions of a? cos a= tan a= csc a=

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

given the sin a=-2/3 and a is in quadrant what are the exact values of the following trigonometric functions of a? cos a= tan a= csc a=

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

what quadrant is a in?
3
Sin=y/r Cos=x/r Tan=y/x Csc=r/r

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

|dw:1433564957553:dw|
And remember that in quadrant 3 only tang is positive
Sinx is negative in the 3rd quadrant
and also in the fourth quadrant
sin=-2/3
Do you know how to approach this question ?
has anyone suggested drawing a triangle yet? it would really make things easy
no not really
the do it label the "opposite side " 2, the hypotenuse 3, and use pythagoras to find the length of the adjacent side
|dw:1433565255841:dw|
5
oh no!
\[2^2+?^2=3^2\\ ?=\sqrt{3^2-2^2}\]
1^2
is it right @satellite73
no not at all
what is \(3^2\)?
9
ok and \(2^2\)?
4
and \[9-4\]?
5
so what is \[\sqrt{3^2-2^2}\]?
5^2?
no dear not \(5^2\) but rather \(\sqrt 5\)
my bad
then what next
Then you use the sides to find the rest of the trig functions
|dw:1433566350237:dw|
now you can take any trig ratio you want, just remember what quadrant you are in to make sure to know if it is positive or negative
so for cos a
so for cos a its 5/3 @satellite73
and for tan a 2/sqrt5
You can't leave a radical in the denominator. You would have to multiply the 2/sqrt5 by sqrt5/sqrt5
so like 3/2sqrt5

Not the answer you are looking for?

Search for more explanations.

Ask your own question