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anonymous
 one year ago
The function f(x) passes through the point (3, 3). If g(x)=f(x3)+4, then which one of these points, if any, must lie on the graph of g(x)?
anonymous
 one year ago
The function f(x) passes through the point (3, 3). If g(x)=f(x3)+4, then which one of these points, if any, must lie on the graph of g(x)?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if \[f(3)=3\] then \[g(0)=f(03)+4=3+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wow thats a lot to process ok so then what

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it does look confusing, but one thing that should not be confusing is that if \[(3,3)\] is on the graph of \(f\) then that measn \[f(3)=3\] right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so that means it equals 7.. what then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you only know what \(f(3)\) is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the only way to know a value for \(g\) is if the input is \(3\) which will be the case if \(x=0\) since \[03=3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if \(x=0\) then \(g(0)=f(03)+4=f(3)+4=7\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that means, on the graph of \(g\) is the point \((0,7)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so how would you do this next one.. i kinda understand. the function f(x) passes through (4,2). If g(x)=f(x), which one of these points must lie on graph of g(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if \(f(4)=2\) the \(g(4)=f(4)=(2)=2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which is a long winded way of saying if \((4,2)\) is on the graph of \(f\) then \((4,2)\) is on the graph of \(f\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wow you are a god. okay ill probably have another question soon dont leave meh

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not a god however, just a satellite
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