Question regarding circuits.

- Curry

Question regarding circuits.

- katieb

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- Curry

##### 1 Attachment

- Curry

the answer is 4/3 + 27.7 cos(20t - 56deg). I was able to get the second part of the answer using super position. However, i don't know where the 4/3 is coming from.

- freckles

what differential equation did you solve?
and how do you tell the initial condition?
if you don't know I'm still browsing the internet

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## More answers

- Curry

well, using super position, I first turned off the 2v voltage source. and then solved for v(t). then i turned off the current source and then solved for v(t) again. Then added these 2 v(t). That gives the second part of the answer.

- Curry

and I didn't use any differential equation, i used phasors.

- freckles

oh looking up that term :p

- freckles

I'm not sure if @ganeshie8 knows about circuits but I will call him here just in case

- Curry

|dw:1433569338362:dw|

- Curry

so solving that for current gives 2v([(10+10j)+(20||-5j)] x (20||-5j) = V1.

- Curry

|dw:1433569640632:dw|

- Curry

Solving that gives V2. V1 + V2 gives the 27.7cos(20t - 56). But i don't get where the 4/3 comes frmo.

- Curry

- freckles

http://www.labsanywhere.net/circuit/lectures/lect10/lecture10.php
this seems to be similar to what you are doing

- freckles

except they solved for i

- Curry

well that circuit is different because it's both AC. My problem is AC and DC. :(

- Curry

well that circuit is different because it's both AC. My problem is AC and DC. :(

- Curry

- Curry

- Curry

- anonymous

CURRY plz come back and help me

- IrishBoy123

2 * 20/30 = 4/3
ie not sure what you are doing but the 2V source surely only goes through the resistors
total impedance to AC is \(5.55 e^{-56^0j}\) giving the right hand part of the desired solution.

- Curry

Why doesn't the 2v go through the inductor and capacitor? I've done a lot of problems with DC circuits and Capacitors and inductors.

- Curry

And calculating the second part of the equation requires both the AC and DC value. When doing it through super position ofc.

- Curry

btw, what major are you Irish boy?

- IrishBoy123

direct current goes through a capacitor? in a dc-C circuit you will get that initial flow as the cap charges up but that's it. it "will" go through the inductor but what is the inductor's resistance?
so the dc to superimpose is flowing through a 10\( \Omega\) and 20\( \Omega\) resistor and you're measuring the drop on the latter.
the AC is a RL/R/C all in parallel.
btw, if he's around, this is "the" chap to tag on this type of stuff: @radar

- Curry

So, when i have a DC and an AC, what should my appraoch be? I usually start with super position. I calculate the voltage drop from the DC and then the AC. and then i add them up. So for this problem, i did that and i got the correct answer for the latter of the equation. but the initial part i couldn't. So generally, is it just, ignore the AC, and short inductors. and open capacitors?

- Curry

- Curry

@IrishBoy123 Hey can you clarify whenever you can?

- Curry

wait nvm. I got it. Thanks so much. you saved my life.

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