anonymous
  • anonymous
which of the following, if any, are polynomial functions?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
yes second one is polynomial .
anonymous
  • anonymous
not the first one because of the variable in the denominator

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anonymous
  • anonymous
you got that? no to the first yes to the second
anonymous
  • anonymous
i dont think all polynomials are functions
anonymous
  • anonymous
yes i understand that.. and just for educational purposes.. what makes something a polynomial function
anonymous
  • anonymous
you have only positive integer exponents
anonymous
  • anonymous
\[p(x)=a_nx^n+a_{n+1}x^{n-1}+...+a_1x+a_0\]
anonymous
  • anonymous
yep satellite explained it
anonymous
  • anonymous
alright and how would you determine the leading coefficient of a polynomial
anonymous
  • anonymous
it is the coefficient of the term of highest degree (larges exponent)
anonymous
  • anonymous
if the polynomial is written in standard form (from highest power to lowest) then it is the first coefficient you see
anonymous
  • anonymous
\[f(x)=-4x^2+3x^2-5x+2\] leading coefficient is \(-4\) for example
anonymous
  • anonymous
okay how about the polynomial: P(x)=3(x-1)(x+3)(2x-5)^2 would it be 3??
anonymous
  • anonymous
no
anonymous
  • anonymous
if you multiply out (in your head) you will get \(3\times4=12\)
anonymous
  • anonymous
satellite the leading coefficient of -4 x^2 +3x^@-5x will be -1 ?
anonymous
  • anonymous
or if you multiply out for real you get \[12 x^4-36 x^3-81 x^2+330 x-225\]but you don't need to do that to see the 12
anonymous
  • anonymous
satellite reply my question i am asking u
anonymous
  • anonymous
i don't understand it, look at what you wrote
anonymous
  • anonymous
@chlobohoe do you see how i got the 12?
anonymous
  • anonymous
yes i saw! cause you multiplied everything out. ima bout to post another question wait up<3
anonymous
  • anonymous
will it be 1 ?http://prntscr.com/7dpfkw
anonymous
  • anonymous
i mean -1
anonymous
  • anonymous
lol i made a typo
anonymous
  • anonymous
lol.its ok but u confused me :P

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