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anonymous

  • one year ago

If a stone is thrown vertically upward from the surface of the moon with a velocity of 10 m/s, its height (in meters) after t seconds is h(t)=10t−0.83t^2 What is the velocity of the stone after it has risen 25 m?

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  1. anonymous
    • one year ago
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    Am I just supposed to set h(t) = 25 and solve the quadratic for t and then plug that t in the derivative of h(t) ?

  2. jim_thompson5910
    • one year ago
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    Yes you have the correct line of thinking.

  3. anonymous
    • one year ago
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    Awesome! But solving the quadratic I will get 2 values for t, which one should I plug in?

  4. jim_thompson5910
    • one year ago
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    |dw:1433569730753:dw|

  5. jim_thompson5910
    • one year ago
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    I guess I should say "smaller t value" instead of "first t value"

  6. anonymous
    • one year ago
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    Great! @jim_thompson5910 I got it! :D Many thanks!

  7. jim_thompson5910
    • one year ago
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    you're welcome

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