which one of the following is a complex zero of P(x)=x^4-16

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which one of the following is a complex zero of P(x)=x^4-16

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[x^4-16=(x^2+4)(x^2-4)=(x^2+4)(x+2)(x-2)\]
the real zeros are \(2\) and \(-2\)
the complex ones you get from solving \[x^2+4=0\] do you know how to do that?

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Other answers:

wouldn't x=2?
no
\[x^2+4=0\\ x^2=-2\\ x=\pm\sqrt{-2}\] or \[x=\pm\sqrt{2}i\]
it is not \(x=2\) because \(2^2+4=4+4=8\) not zero
okay so what if my choices are only..
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i made a typo there second line should be \(x^2=-4\)
\(-2i\) and \(2i\) are the zeros pick \(-2i\) who is jsara?
okay that makes sense.... and i just typed in random letters but I asked myself that same question as i was sending it hahahaha
if those letters are random i will have a beer now

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