## anonymous one year ago graph questions...

1. anonymous

2. anonymous

looks from my eyes that $$-3$$ is one zero, crosses touches the x axis there

3. anonymous

yeah i was thinking -3,-5,5

4. anonymous

then look to see the other point where it crosses the x axis

5. anonymous

no not $$-5$$

6. anonymous

well then what would it be considering the choices

7. anonymous

it does not cross the x axis at -5

8. anonymous

do you have a choice that says $$-3$$ and $$5$$?

9. anonymous

you are only being asked where it touches or crosses the x axis

10. jim_thompson5910

see attached image

11. anonymous

the choices are on with the graph.. and theres a -3,-3,5

12. anonymous

lol no you don't

13. anonymous

go with NONE OF THESE

14. anonymous

don't pick a wrong one just because it is there

15. anonymous

thats reasonable hahaha okay heres the next one

16. anonymous

17. anonymous

name the zeros first

18. anonymous

if you don't know them say so and i will help

19. anonymous

-3,2,4??

20. anonymous

yes

21. anonymous

ok good now we can continue

22. anonymous

you see how it touches at $$-3$$ rather than crossing?

23. anonymous

yes

24. anonymous

that means one of the factors is $$(x+3)^2$$ rather than just $$x+3$$

25. anonymous

then the answer would be B??

26. anonymous

hold the phone we are not done

27. anonymous

oh lol yeah sorry

28. anonymous

by process of elimination that is the only one with $$(x+3)^2$$ in it

29. anonymous

you should also have a $$(x-2)^2$$ as a factor, and $$x-4$$ so yeah $(x+3)^2(x-2)^2(x-4)$

30. anonymous

okay that one was easy! heres the last graph one.. i think

31. anonymous

looks like the zeros are at $$-3$$ and also $$4$$

32. anonymous

oh and at $$-1$$

33. anonymous

yessss i got that :) so then

34. anonymous

and it touches at $$4$$ so it is going to look like this $a(x+3)(x+1)(x-4)^2$

35. anonymous

did you get that part?

36. anonymous

yessss got that also

37. anonymous

i hope it is clear $$-3$$ is a zero, so one factor is $$x+3$$ $$-1$$ is a zero so one factor is $$x+1$$ and $$4$$ is a zero, it touches at 4 so one factor is $$x-4$$ ok good

38. anonymous

now we need $$a$$

39. anonymous

$$(3,-6)$$ is on the graph that means if $$x=3$$ you should get $$-6$$ as a result

40. anonymous

set $a(3+3)(3+1)(3-4)^2=-6$ and solve for $$a$$

41. anonymous

which is not has hard as it looks since $$(3-4)^2=(-1)^2=1$$ so you really only have $a\times 6\times 4=-6$

42. anonymous

-1/4??

43. anonymous

i get $a=-\frac{1}{4}$ but it is late, check my algebra

44. anonymous

oh look, C! it is always C go with C

45. anonymous

i suppose "ihatethis" is random letters as wel

46. anonymous

you done or got more?

47. anonymous

hahah okay ill go with C! thank you. ok now onto matrices..

48. anonymous

oh god