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anonymous

  • one year ago

graph questions...

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    looks from my eyes that \(-3\) is one zero, crosses touches the x axis there

  3. anonymous
    • one year ago
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    yeah i was thinking -3,-5,5

  4. anonymous
    • one year ago
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    then look to see the other point where it crosses the x axis

  5. anonymous
    • one year ago
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    no not \(-5\)

  6. anonymous
    • one year ago
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    well then what would it be considering the choices

  7. anonymous
    • one year ago
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    it does not cross the x axis at -5

  8. anonymous
    • one year ago
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    do you have a choice that says \(-3\) and \(5\)?

  9. anonymous
    • one year ago
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    you are only being asked where it touches or crosses the x axis

  10. jim_thompson5910
    • one year ago
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    see attached image

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  11. anonymous
    • one year ago
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    the choices are on with the graph.. and theres a -3,-3,5

  12. anonymous
    • one year ago
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    lol no you don't

  13. anonymous
    • one year ago
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    go with NONE OF THESE

  14. anonymous
    • one year ago
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    don't pick a wrong one just because it is there

  15. anonymous
    • one year ago
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    thats reasonable hahaha okay heres the next one

  16. anonymous
    • one year ago
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  17. anonymous
    • one year ago
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    name the zeros first

  18. anonymous
    • one year ago
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    if you don't know them say so and i will help

  19. anonymous
    • one year ago
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    -3,2,4??

  20. anonymous
    • one year ago
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    yes

  21. anonymous
    • one year ago
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    ok good now we can continue

  22. anonymous
    • one year ago
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    you see how it touches at \(-3\) rather than crossing?

  23. anonymous
    • one year ago
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    yes

  24. anonymous
    • one year ago
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    that means one of the factors is \((x+3)^2\) rather than just \(x+3\)

  25. anonymous
    • one year ago
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    then the answer would be B??

  26. anonymous
    • one year ago
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    hold the phone we are not done

  27. anonymous
    • one year ago
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    oh lol yeah sorry

  28. anonymous
    • one year ago
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    by process of elimination that is the only one with \((x+3)^2\) in it

  29. anonymous
    • one year ago
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    you should also have a \((x-2)^2\) as a factor, and \(x-4\) so yeah \[(x+3)^2(x-2)^2(x-4)\]

  30. anonymous
    • one year ago
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    okay that one was easy! heres the last graph one.. i think

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  31. anonymous
    • one year ago
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    looks like the zeros are at \(-3\) and also \(4\)

  32. anonymous
    • one year ago
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    oh and at \(-1\)

  33. anonymous
    • one year ago
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    yessss i got that :) so then

  34. anonymous
    • one year ago
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    and it touches at \(4\) so it is going to look like this \[a(x+3)(x+1)(x-4)^2\]

  35. anonymous
    • one year ago
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    did you get that part?

  36. anonymous
    • one year ago
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    yessss got that also

  37. anonymous
    • one year ago
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    i hope it is clear \(-3\) is a zero, so one factor is \(x+3\) \(-1\) is a zero so one factor is \(x+1\) and \(4\) is a zero, it touches at 4 so one factor is \(x-4\) ok good

  38. anonymous
    • one year ago
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    now we need \(a\)

  39. anonymous
    • one year ago
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    \((3,-6)\) is on the graph that means if \(x=3\) you should get \(-6\) as a result

  40. anonymous
    • one year ago
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    set \[a(3+3)(3+1)(3-4)^2=-6\] and solve for \(a\)

  41. anonymous
    • one year ago
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    which is not has hard as it looks since \((3-4)^2=(-1)^2=1\) so you really only have \[a\times 6\times 4=-6\]

  42. anonymous
    • one year ago
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    -1/4??

  43. anonymous
    • one year ago
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    i get \[a=-\frac{1}{4}\] but it is late, check my algebra

  44. anonymous
    • one year ago
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    oh look, C! it is always C go with C

  45. anonymous
    • one year ago
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    i suppose "ihatethis" is random letters as wel

  46. anonymous
    • one year ago
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    you done or got more?

  47. anonymous
    • one year ago
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    hahah okay ill go with C! thank you. ok now onto matrices..

  48. anonymous
    • one year ago
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    oh god

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