graph questions...

- anonymous

graph questions...

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- anonymous

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- anonymous

looks from my eyes that \(-3\) is one zero, crosses touches the x axis there

- anonymous

yeah i was thinking -3,-5,5

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- anonymous

then look to see the other point where it crosses the x axis

- anonymous

no not \(-5\)

- anonymous

well then what would it be considering the choices

- anonymous

it does not cross the x axis at -5

- anonymous

do you have a choice that says \(-3\) and \(5\)?

- anonymous

you are only being asked where it touches or crosses the x axis

- jim_thompson5910

see attached image

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- anonymous

the choices are on with the graph.. and theres a -3,-3,5

- anonymous

lol no you don't

- anonymous

go with NONE OF THESE

- anonymous

don't pick a wrong one just because it is there

- anonymous

thats reasonable hahaha okay heres the next one

- anonymous

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- anonymous

name the zeros first

- anonymous

if you don't know them say so and i will help

- anonymous

-3,2,4??

- anonymous

yes

- anonymous

ok good now we can continue

- anonymous

you see how it touches at \(-3\) rather than crossing?

- anonymous

yes

- anonymous

that means one of the factors is \((x+3)^2\) rather than just \(x+3\)

- anonymous

then the answer would be B??

- anonymous

hold the phone we are not done

- anonymous

oh lol yeah sorry

- anonymous

by process of elimination that is the only one with \((x+3)^2\) in it

- anonymous

you should also have a \((x-2)^2\) as a factor, and \(x-4\) so yeah
\[(x+3)^2(x-2)^2(x-4)\]

- anonymous

okay that one was easy! heres the last graph one.. i think

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- anonymous

looks like the zeros are at \(-3\) and also \(4\)

- anonymous

oh and at \(-1\)

- anonymous

yessss i got that :) so then

- anonymous

and it touches at \(4\) so it is going to look like this
\[a(x+3)(x+1)(x-4)^2\]

- anonymous

did you get that part?

- anonymous

yessss got that also

- anonymous

i hope it is clear
\(-3\) is a zero, so one factor is \(x+3\)
\(-1\) is a zero so one factor is \(x+1\) and
\(4\) is a zero, it touches at 4 so one factor is \(x-4\) ok good

- anonymous

now we need \(a\)

- anonymous

\((3,-6)\) is on the graph
that means if \(x=3\) you should get \(-6\) as a result

- anonymous

set \[a(3+3)(3+1)(3-4)^2=-6\] and solve for \(a\)

- anonymous

which is not has hard as it looks since \((3-4)^2=(-1)^2=1\) so you really only have
\[a\times 6\times 4=-6\]

- anonymous

-1/4??

- anonymous

i get
\[a=-\frac{1}{4}\] but it is late, check my algebra

- anonymous

oh look, C! it is always C
go with C

- anonymous

i suppose "ihatethis" is random letters as wel

- anonymous

you done or got more?

- anonymous

hahah okay ill go with C! thank you. ok now onto matrices..

- anonymous

oh god

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