anonymous
  • anonymous
graph questions...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
looks from my eyes that \(-3\) is one zero, crosses touches the x axis there
anonymous
  • anonymous
yeah i was thinking -3,-5,5

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anonymous
  • anonymous
then look to see the other point where it crosses the x axis
anonymous
  • anonymous
no not \(-5\)
anonymous
  • anonymous
well then what would it be considering the choices
anonymous
  • anonymous
it does not cross the x axis at -5
anonymous
  • anonymous
do you have a choice that says \(-3\) and \(5\)?
anonymous
  • anonymous
you are only being asked where it touches or crosses the x axis
jim_thompson5910
  • jim_thompson5910
see attached image
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anonymous
  • anonymous
the choices are on with the graph.. and theres a -3,-3,5
anonymous
  • anonymous
lol no you don't
anonymous
  • anonymous
go with NONE OF THESE
anonymous
  • anonymous
don't pick a wrong one just because it is there
anonymous
  • anonymous
thats reasonable hahaha okay heres the next one
anonymous
  • anonymous
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anonymous
  • anonymous
name the zeros first
anonymous
  • anonymous
if you don't know them say so and i will help
anonymous
  • anonymous
-3,2,4??
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok good now we can continue
anonymous
  • anonymous
you see how it touches at \(-3\) rather than crossing?
anonymous
  • anonymous
yes
anonymous
  • anonymous
that means one of the factors is \((x+3)^2\) rather than just \(x+3\)
anonymous
  • anonymous
then the answer would be B??
anonymous
  • anonymous
hold the phone we are not done
anonymous
  • anonymous
oh lol yeah sorry
anonymous
  • anonymous
by process of elimination that is the only one with \((x+3)^2\) in it
anonymous
  • anonymous
you should also have a \((x-2)^2\) as a factor, and \(x-4\) so yeah \[(x+3)^2(x-2)^2(x-4)\]
anonymous
  • anonymous
okay that one was easy! heres the last graph one.. i think
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anonymous
  • anonymous
looks like the zeros are at \(-3\) and also \(4\)
anonymous
  • anonymous
oh and at \(-1\)
anonymous
  • anonymous
yessss i got that :) so then
anonymous
  • anonymous
and it touches at \(4\) so it is going to look like this \[a(x+3)(x+1)(x-4)^2\]
anonymous
  • anonymous
did you get that part?
anonymous
  • anonymous
yessss got that also
anonymous
  • anonymous
i hope it is clear \(-3\) is a zero, so one factor is \(x+3\) \(-1\) is a zero so one factor is \(x+1\) and \(4\) is a zero, it touches at 4 so one factor is \(x-4\) ok good
anonymous
  • anonymous
now we need \(a\)
anonymous
  • anonymous
\((3,-6)\) is on the graph that means if \(x=3\) you should get \(-6\) as a result
anonymous
  • anonymous
set \[a(3+3)(3+1)(3-4)^2=-6\] and solve for \(a\)
anonymous
  • anonymous
which is not has hard as it looks since \((3-4)^2=(-1)^2=1\) so you really only have \[a\times 6\times 4=-6\]
anonymous
  • anonymous
-1/4??
anonymous
  • anonymous
i get \[a=-\frac{1}{4}\] but it is late, check my algebra
anonymous
  • anonymous
oh look, C! it is always C go with C
anonymous
  • anonymous
i suppose "ihatethis" is random letters as wel
anonymous
  • anonymous
you done or got more?
anonymous
  • anonymous
hahah okay ill go with C! thank you. ok now onto matrices..
anonymous
  • anonymous
oh god

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