matrix 2

- anonymous

matrix 2

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- anonymous

##### 1 Attachment

- anonymous

ihatethisevenmoremore

- anonymous

it is not C

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## More answers

- anonymous

this takes a bit but not too bad
ready?

- anonymous

this is where you say "yeah i am ready even though i hate this even more"

- anonymous

yeah i am ready even though i hate this even more

- anonymous

ok the last line has 1, -2 which means \(z=-2\)

- anonymous

the second to last line has 1, 1, 3 which means \[y+z=3\] we know \(z=-2\) so
\[y-2=3\]or
\[y=5\]

- anonymous

the first line has 1, a, 2, 2 which means
\[x+ay+2z=2\] we know \(y=5\) and \(z=-2\) so we have
\[x+4a+2\times (-2)=2\] or
\[x+5a-4=2\]

- anonymous

solve for \(a\) and get your answer
you can do it or you want help?

- anonymous

oops i meant "solve for \(x\)"

- anonymous

its B? then

- anonymous

yeah B

- anonymous

okay 1 or 2 more then i promise ill let you go :'(

- anonymous

i have to say for someone starting out with matrices this is a dumb question but whatever

- anonymous

yeah i always stay up until 3 to help...

- anonymous

##### 1 Attachment

- anonymous

I think its D?

- anonymous

@freckles this one is on you, i always screw this up

- anonymous

C is out

- anonymous

i mean matrix C is out

- anonymous

oh maybe not let me shut up

- freckles

if we do a m by n times a n by k
the we are cool because this will result in a m by k matrix
you just have to make sure
the inner numbers match if you know what I mean

- freckles

|dw:1433573306445:dw|

- anonymous

so BA is ok right?

- freckles

|dw:1433573324663:dw|

- anonymous

and CB?

- anonymous

okay so can CB not work or

- anonymous

CB ok [2,4][4,1] right?

- anonymous

oh wait so it's E then??

- freckles

AB will not work
since we have a 1 by 3 times a 4 by 1
3 is not 4
BA will work
since we have a 4 by 1 times 1 by 3
1 is 1
CB will work
2 by 4 times 4 by 1
because 4 is 4

- anonymous

ok ok so LAST ONE

##### 1 Attachment

- anonymous

cheat

- anonymous

otherwise this is total donkey work that takes like forever with very little bang for your buck
it is for a machine, let the machine do it
http://www.wolframalpha.com/input/?i=x-2y-z%3D2%2Cy%2B3z%3D1%2C2x-4y-3z%3D3

- anonymous

you got this?

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