## anonymous one year ago Set up an integral that represents the area bounded by y = x^2 and y =abs( x)

1. Jack1

graph attached

2. Jack1

so as u can see, the area bounded by these 2 lines is between (-1,1) to (0,0) then 0,0 to 1,1

3. welshfella

|dw:1433587773344:dw|

4. Jack1

|dw:1433588439697:dw| don't forget it's absolute value of x... otherwise wont work for -ve x values section I think...? @welshfella

5. Jack1

$\Large \int\limits_{0}^{1}(\left| x \right| -x^2)~ dx + \int\limits_{-1}^{0}(\left| x \right| -x^2)~ dx$

6. welshfella

it does not matter because the integral of x is x^2/2 which will give a positive value anyway

7. Jack1

true... sorry

8. welshfella

as the 2 areas each side of the y axis are the same you could write it as |dw:1433590128375:dw|

9. welshfella

- easier to work out