anonymous
  • anonymous
Set up an integral that represents the area bounded by y = x^2 and y =abs( x)
Mathematics
chestercat
  • chestercat
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Jack1
  • Jack1
graph attached
1 Attachment
Jack1
  • Jack1
so as u can see, the area bounded by these 2 lines is between (-1,1) to (0,0) then 0,0 to 1,1
welshfella
  • welshfella
|dw:1433587773344:dw|

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Jack1
  • Jack1
|dw:1433588439697:dw| don't forget it's absolute value of x... otherwise wont work for -ve x values section I think...? @welshfella
Jack1
  • Jack1
\[\Large \int\limits_{0}^{1}(\left| x \right| -x^2)~ dx + \int\limits_{-1}^{0}(\left| x \right| -x^2)~ dx\]
welshfella
  • welshfella
it does not matter because the integral of x is x^2/2 which will give a positive value anyway
Jack1
  • Jack1
true... sorry
welshfella
  • welshfella
as the 2 areas each side of the y axis are the same you could write it as |dw:1433590128375:dw|
welshfella
  • welshfella
- easier to work out

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