At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

What are you using for frequency?

20

sorry i mean 50.

Well I thought (10 + 20j ) || -j/50C = 30.

Cause i'd use the R thevenin.

the answer the gave was 0.8mF. and when i plug that into the equation I typed above, i got 50. :/

It represents a real (resistor) value of 10 and a series inductive reactance of 20 Ohms.

ok if it would have been a capacitor then Z=10-20j right?

yes

because the equation is -J/wc

yeah i get that for the max power but um kinda confused with the signs

So wait, sorry, back to my question, where am I going wrong?

In other words, the inductor's value would have been 2/5.

Hope that helps.

yes, that is correct.

so in other words your value for the capicatance impedance is -J/50C. We just have to solve for C.

That is much larger 1,000 micro farad vs .8 microfarad.

|dw:1433647505784:dw|

Here's a better picture -

well the answer he posted was 0.8mF. so, i'm guesing he derived an acutal value.