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horsegirl27

  • one year ago

Help me I'm so confused!!

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  1. horsegirl27
    • one year ago
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    http://prntscr.com/7dszf6 I may be able to do the rest myself when I understand the first part.

  2. horsegirl27
    • one year ago
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    @Mr_Perfection_xD @radar @rational @kentucky

  3. horsegirl27
    • one year ago
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    Please help!

  4. horsegirl27
    • one year ago
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    I will medal and fan

  5. anonymous
    • one year ago
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    Well, let's find the inverse of f(x) without plugging in any numbers. That way we can see the relationship between a, b, c, and d that we need. If we start with \(y = \frac{x+a}{b}\), we can find the inverse by exchanging the variables x and y and then resoving for y. \(y = \frac{x+a}{b}\) becomes \(x = \frac{y+a}{b}\) Now solving for y, we get: \[x = \frac{ y+a }{ b }\] \[bx = y+a\] \[bx-a = y\] Now compare our result with g(x). We have \(f^{-1}(x) = bx-a\) and we want it to look like \(g(x) = cx-d\). So these two will be equal to each other if b = c and a =d. Can you see that?

  6. anonymous
    • one year ago
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    @horsegirl27

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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