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horsegirl27
 one year ago
Help me I'm so confused!!
horsegirl27
 one year ago
Help me I'm so confused!!

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horsegirl27
 one year ago
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horsegirl27
 one year ago
Best ResponseYou've already chosen the best response.0@Mr_Perfection_xD @radar @rational @kentucky

horsegirl27
 one year ago
Best ResponseYou've already chosen the best response.0I will medal and fan

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, let's find the inverse of f(x) without plugging in any numbers. That way we can see the relationship between a, b, c, and d that we need. If we start with \(y = \frac{x+a}{b}\), we can find the inverse by exchanging the variables x and y and then resoving for y. \(y = \frac{x+a}{b}\) becomes \(x = \frac{y+a}{b}\) Now solving for y, we get: \[x = \frac{ y+a }{ b }\] \[bx = y+a\] \[bxa = y\] Now compare our result with g(x). We have \(f^{1}(x) = bxa\) and we want it to look like \(g(x) = cxd\). So these two will be equal to each other if b = c and a =d. Can you see that?
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