horsegirl27
  • horsegirl27
Help me I'm so confused!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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horsegirl27
  • horsegirl27
http://prntscr.com/7dszf6 I may be able to do the rest myself when I understand the first part.
horsegirl27
  • horsegirl27
@Mr_Perfection_xD @radar @rational @kentucky
horsegirl27
  • horsegirl27
Please help!

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horsegirl27
  • horsegirl27
I will medal and fan
anonymous
  • anonymous
Well, let's find the inverse of f(x) without plugging in any numbers. That way we can see the relationship between a, b, c, and d that we need. If we start with \(y = \frac{x+a}{b}\), we can find the inverse by exchanging the variables x and y and then resoving for y. \(y = \frac{x+a}{b}\) becomes \(x = \frac{y+a}{b}\) Now solving for y, we get: \[x = \frac{ y+a }{ b }\] \[bx = y+a\] \[bx-a = y\] Now compare our result with g(x). We have \(f^{-1}(x) = bx-a\) and we want it to look like \(g(x) = cx-d\). So these two will be equal to each other if b = c and a =d. Can you see that?
anonymous
  • anonymous
@horsegirl27

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