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anonymous
 one year ago
Can someone PLEASE HELP ME OUT with capacitors in series?
anonymous
 one year ago
Can someone PLEASE HELP ME OUT with capacitors in series?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know @shaurya?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when you add capacitors in series then they get added in the way resistances are added in parallel

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0? If you connect 2 cables of 10μF in a total charge of 20V,whatI would be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah but idk what to do with that 10μF

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0consider the two wires as capacitors each of 10uF

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry I really have no idea, we never used this unit before

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you please help me out with this one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solve it as any other unit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you show me how to solve this one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or just from where to start?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One farad is defined as the capacitance of a capacitor across which, when charged with one coulomb of electricity, there is a potential difference of one volt.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so here it will be 20 volt, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they ask me here what the voltage on each cable is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in series 1/C equivalent = 1/c1 + 1/c2 so c equivalent will be 5 uF

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Vcx = Vs* (Ct/Cx) Where: CX is the capacitance of the capacitor in question, VS is the supply voltage across the series chain and VCX is the voltage drop across the target capacitor.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you are satisfied then give me a medal or say so
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