At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
do you know @shaurya?
when you add capacitors in series then they get added in the way resistances are added in parallel
? If you connect 2 cables of 10μF in a total charge of 20V,whatI would be?
yeah but idk what to do with that 10μF
consider the two wires as capacitors each of 10uF
sorry I really have no idea, we never used this unit before
can you please help me out with this one?
solve it as any other unit
can you show me how to solve this one?
or just from where to start?
One farad is defined as the capacitance of a capacitor across which, when charged with one coulomb of electricity, there is a potential difference of one volt.
so here it will be 20 volt, right?
they ask me here what the voltage on each cable is
in series 1/C equivalent = 1/c1 + 1/c2 so c equivalent will be 5 uF
Vcx = Vs* (Ct/Cx) Where: CX is the capacitance of the capacitor in question, VS is the supply voltage across the series chain and VCX is the voltage drop across the target capacitor.
its the formula
if you are satisfied then give me a medal or say so