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anonymous

  • one year ago

How do you find the complex roots of a polynomial?

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  1. anonymous
    • one year ago
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    Do you have an example? The process could be different depending on what you have.

  2. anonymous
    • one year ago
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    4x^3 – 12x + 9 = 0 Something like this... The example my teacher gave to me said that because equation has a degree of 3 it has 3 complex roots... and i think im interpreting that wrong

  3. anonymous
    • one year ago
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    Its impossible to have 3 complex roots. There can only be an even number of roots.

  4. anonymous
    • one year ago
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    even number of complex I mean

  5. anonymous
    • one year ago
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    he said that for imaginary roots

  6. anonymous
    • one year ago
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    Yeah, complex roots and imaginary roots you can consider to be the same thing. There must be an even number of imaginary roots. So this cubic either has 2 imaginary roots or 0.

  7. anonymous
    • one year ago
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    okay so it can be either one? or do i have to find out which one?

  8. anonymous
    • one year ago
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    Yes, you might have 2 imaginary or you might have 0 imaginary. You would want to ty and see if you could factor the cubic and find its zeros first.

  9. anonymous
    • one year ago
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    Okay! Thanks for clearing that up for me!

  10. anonymous
    • one year ago
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    Mhm, sure. If you had to actually do this problem, though, it appears that it wont factor cleanly. The best you could do is show that it does have 1 real zero and that there cant be another real zero. So yeah, this problem has 2 imaginary roots.

  11. anonymous
    • one year ago
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    Thanks!

  12. anonymous
    • one year ago
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    No problem

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