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kanwal32
 one year ago
how to write the equation of projectile after it has reached its maximum height(suppose at time t1 and t2 there are at same height) without finding the the time taken to reach at it full height
kanwal32
 one year ago
how to write the equation of projectile after it has reached its maximum height(suppose at time t1 and t2 there are at same height) without finding the the time taken to reach at it full height

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kanwal32
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino pls help in hurry i want to solve this doubt

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0in general I solve that type of problem using vectors equations, namely: \[\large \left\{ \begin{gathered} {\mathbf{OP}}\left( t \right) = {\mathbf{O}}{{\mathbf{P}}_{\mathbf{0}}} + {{\mathbf{v}}_{\mathbf{0}}}t + \frac{1}{2}{\mathbf{g}}{t^2} \hfill \\ {\mathbf{v}}\left( t \right) = {{\mathbf{v}}_{\mathbf{0}}} + {\mathbf{g}}t \hfill \\ \end{gathered} \right.\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0Then I consider a reference frame and I will rewrite those equations in that reference frame

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0for example, if we pick the subsequent reference frame: dw:1433609868699:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0then those vector equation can be rewritten as follows: \[\Large \begin{gathered} \left\{ \begin{gathered} z\left( t \right) = {z_0} + {v_0}\left( {\sin \theta } \right)t  \frac{1}{2}g{t^2} \hfill \\ x\left( t \right) = {x_0} + {v_0}\left( {\cos \theta } \right)t \hfill \\ \end{gathered} \right. \hfill \\ \hfill \\ \left\{ \begin{gathered} {v_z}\left( t \right) = {v_0}\left( {\sin \theta } \right)  gt \hfill \\ {v_x}\left( t \right) = {v_0}\left( {\cos \theta } \right) \hfill \\ \end{gathered} \right. \hfill \\ \end{gathered} \] dw:1433610127064:dw
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