anonymous
  • anonymous
In a series circuit with 9V battery and two resistors, one 100 Ohms and one at 350 Ohms, this is the voltage across each one respectively. **What is that voltage?
Physics
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anonymous
  • anonymous
In a series circuit with 9V battery and two resistors, one 100 Ohms and one at 350 Ohms, this is the voltage across each one respectively. **What is that voltage?
Physics
katieb
  • katieb
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Michele_Laino
  • Michele_Laino
the current in your circuit is: \[\Large I = \frac{{\Delta V}}{{{R_1} + {R_2}}} = \frac{9}{{100 + 350}}\] since your resistors are connected in series, and the equivalent resistance is: R_1+R_2 |dw:1433611823658:dw|
anonymous
  • anonymous
ok! and solving we get 0.02?
Michele_Laino
  • Michele_Laino
correct!

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anonymous
  • anonymous
is that the voltage across each one? :/ 0.02 is our solution?
Michele_Laino
  • Michele_Laino
now using the Ohm's law, we can compute the requested voltage drop as below: |dw:1433612018865:dw| \[\Large \begin{gathered} \Delta {V_1} = I \times {R_1} = 0.02 \times 100 \hfill \\ \Delta {V_2} = I \times {R_2} = 0.02 \times 350 \hfill \\ \end{gathered} \]
anonymous
  • anonymous
2 & 7? so those are our solution? 2 and 7 ?
anonymous
  • anonymous
is it ohms as well? :/
Michele_Laino
  • Michele_Laino
yes! 2 volts, and 7 volts
anonymous
  • anonymous
oh oops volts haha :P
anonymous
  • anonymous
yay so this problem is complete? :O
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
yay!! thank you!:D
Michele_Laino
  • Michele_Laino
:)
Michele_Laino
  • Michele_Laino
please, as you can check, we have: 2 +7 = 9 volts which is the voltage of our battery
anonymous
  • anonymous
ohh yes:) thank you!!:D

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