## anonymous one year ago A 10m wire that carries a current of 3A from east to west is placed in a magnetic field of 0.0004T running from south to north. Find the size and direction of the magnetic force on the wire. **how do we find this? :/ Thanks!!:)

1. Michele_Laino

the situation described into your problem is: |dw:1433612353948:dw|

2. anonymous

ok!

3. Michele_Laino

since magnetic field and current are perpendicular each other, then the magnitude of the magnetic force is: $\Large F = ILB$ where L = 10 meters

4. anonymous

yes:)

5. Michele_Laino

namely: $\Large F = ILB = 3 \times 10 \times 4 \times {10^{ - 4}}$

6. anonymous

ok so we get 0.012?

7. Michele_Laino

yes! correct the unit of measure is Newtons, so we have: F= 0.012 Newtons

8. anonymous

is that the size of the force? :/

9. Michele_Laino

yes! now the direction is given by the rule of product vector, so the orientation of the magnetic force is like below: |dw:1433612811550:dw| namely the vector F is perpendicular to both current and magnetic field, and it is oriented inward of the drawing plane

10. anonymous

ok! so it is going south?

11. Michele_Laino

no, it is going inward of the drawing plane, here is a 3-D view: |dw:1433613109921:dw|

12. anonymous

ohh so it is going northeast?

13. Michele_Laino

no, that is a 3-D view not a 2-D view

14. anonymous

ohh i am confused then haha what direction is that ? :/

15. Michele_Laino

it is perpendicular with respect to North-South direction and it also is perpendicular with respect to West-East direction

16. anonymous

ohh okay :/ wow confusing hahah :P thank you!! so this problem is complete?

17. Michele_Laino

yes!

18. anonymous

yay thank you1!:D

19. Michele_Laino

:)