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anonymous

  • one year ago

Divide. Assume the denominator does not equal zero. (18x^5y^3+6x^2y^4+24x^6y) ÷ 3xy Can you please show me how to do this with work?

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  1. anonymous
    • one year ago
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    \[\frac{ 6 x^2y(3x^3y^2+y^3+4 x^4) }{ 3xy }\] =?

  2. anonymous
    • one year ago
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    SO, 18x^5y^3 / 3xy 6x^2y^4/3xy 24x^6y = 6x^4y^2+2xy^3+8x^5 ?

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