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gabbyalicorn

  • one year ago

The prism has a surface area of 202 ft2. What would the surface area of the prism be if each dimension were tripled?

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  1. gabbyalicorn
    • one year ago
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  2. Michele_Laino
    • one year ago
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    the new dimensions are: 5*3=... 9*3=... 4*3=...

  3. gabbyalicorn
    • one year ago
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    15 27 and 12

  4. Michele_Laino
    • one year ago
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    correct!

  5. gabbyalicorn
    • one year ago
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    then x by them?

  6. gabbyalicorn
    • one year ago
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    which us 4860

  7. Michele_Laino
    • one year ago
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    please wait a moment, I'm checking your computation

  8. gabbyalicorn
    • one year ago
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    kk

  9. Michele_Laino
    • one year ago
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    your problem asks for the area of the total surface of the prism. Now the area of the total surface of your prism is given by the subsequent computation: A=2*(15*27+ 15*12+27*12)=...

  10. gabbyalicorn
    • one year ago
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    i got 121608

  11. gabbyalicorn
    • one year ago
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    is that correct?

  12. Michele_Laino
    • one year ago
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    here more steps: \[\Large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = ... \hfill \\ \end{gathered} \]

  13. gabbyalicorn
    • one year ago
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    1314

  14. Michele_Laino
    • one year ago
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    I got a different result

  15. gabbyalicorn
    • one year ago
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    wait do we add the two together?

  16. Michele_Laino
    • one year ago
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    yes!

  17. gabbyalicorn
    • one year ago
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    i got 122922

  18. Michele_Laino
    • one year ago
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    you have to compute this: 405+180+324=... \[\large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = \hfill \\ \hfill \\ = 2 \times 909 = ... \hfill \\ \end{gathered} \]

  19. gabbyalicorn
    • one year ago
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    1818 plus 122922 = 124740

  20. Michele_Laino
    • one year ago
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    no, it is: A= 1818 feet^2 only

  21. gabbyalicorn
    • one year ago
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    -3- hm?

  22. gabbyalicorn
    • one year ago
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    I didnt get that, sorry. :/

  23. Michele_Laino
    • one year ago
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    the new area of the total surface is, namely your answer, is: \[\Large \begin{gathered} A = 2 \times \left( {15 \times 27 + 15 \times 12 + 27 \times 12} \right) = \hfill \\ \hfill \\ = 2 \times \left( {405 + 180 + 324} \right) = \hfill \\ \hfill \\ = 2 \times 909 = 1818fee{t^2} \hfill \\ \end{gathered} \]

  24. gabbyalicorn
    • one year ago
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    oh :l

  25. gabbyalicorn
    • one year ago
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    i see now...

  26. Michele_Laino
    • one year ago
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    since we have to sum the area of all of the six sides of your prism

  27. gabbyalicorn
    • one year ago
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    so 10908? 1818 x 6

  28. Michele_Laino
    • one year ago
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    no, we have finished, your answer is: A= 1818 feet^2

  29. gabbyalicorn
    • one year ago
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    oh kk. Thank you!!! ^u^

  30. Michele_Laino
    • one year ago
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    :)

  31. jim_thompson5910
    • one year ago
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    Old Surface Area = 202 ft^2 New Surface Area = 1818 ft^2 Notice we have this ratio: (new area)/(old area) = 1818/202 = 9 and how 3^2 = 9. This is no coincidence. The old surface area is multiplied by 3^2 = 9 to get the new surface area. If you asked "What would the surface area of the prism be if each dimension were quadrupled?", then you would multiply the old surface area by 4^2 = 16 to get the new surface area

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