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anonymous
 one year ago
f(x) = 3 + x^2 + tan (pix/2)
anonymous
 one year ago
f(x) = 3 + x^2 + tan (pix/2)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Any one can help me with this derivative of an inverse

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1wait so your looking to take the derivative of this equation or what exactly?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes Im in the last part but I dont get quite the exact answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get (pi sec^2 pix/2)/(2) + 2x

freckles
 one year ago
Best ResponseYou've already chosen the best response.3why do you say derivative of inverse ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3Do you mean just find derivative?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1so 3 gets deleted x^2 turns into 2x and tan(pix/2) = sec^2x(pix/2) times the derivative of pix/2 which i believe equates to pi/2. I am not sure if this is totally correct so ya check with someone else.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1so it would look like 2x+sec^2x(pix/2)(pi/2) I think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, i evaluated at 0 but i get pi^2/4

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1x+sec^2(pix/2)(pi/2) is the correct value I accidentally left in x above.

freckles
 one year ago
Best ResponseYou've already chosen the best response.3I'm still confused why you said inverse

freckles
 one year ago
Best ResponseYou've already chosen the best response.3are you wanting to find \[(f^{1})'(a)\] for some number a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I used a couple of engines and I get (pi*sec^2(pix/2)(2))/ + 2x

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1@Eco1 you you are right I made a typo and left out the 2 in front of the x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I evaluate what I wrote above at zero but I dont get pi/2, which is the right asnwer

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[(f^{1})'(3)=\frac{1}{f'(f^{1}(3))} \\ f^{1}(3)=? \implies f(?)=3 \\ \text{ so we need \to find ? such that }3=3+?^2+\tan(\frac{\pi ?}{2}) \\ \text{ and yes } f'(x)=0+2x+\frac{\pi}{2} \sec^2(\frac{\pi}{2}x)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3that should be pretty easy to find ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3because we know both tan(0)=0 and 0^2=0

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[(f^{1})'(3)=\frac{1}{f'(0)}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3last thing for you to do is just to plug in 0 into your f' you found

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did multiple times but I dont get the right answer

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[f'(0)=2(0)+\frac{\pi}{2}[\sec(\frac{\pi}{2}(0))]^2\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3well first the inside of that sec( ) thing you can be simplified pi/2*0=0 so sec(0)=?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3\[(f^{1})'(3)=\frac{1}{f'(0)}=\frac{1}{2(0)+\frac{\pi}{2}[\sec(0)]^2}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3you know cos(0)=1 so sec(0)=?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3hint sec and cos are reciprocal functions of each other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0reciprocal is synonym of inverse?

freckles
 one year ago
Best ResponseYou've already chosen the best response.3it depends what inverse you are talking about multiplicative inverse yeah

freckles
 one year ago
Best ResponseYou've already chosen the best response.3like sec(x)=1/cos(x) so sec(0)=1/cos(0)

freckles
 one year ago
Best ResponseYou've already chosen the best response.31/cos(x) is reciprocal of cos(x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.3some people just like to call it the flipping of

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but it is sec(0)^2 not sec(0)

freckles
 one year ago
Best ResponseYou've already chosen the best response.3if cos(0)=1 then sec(0)=1/cos(0)=1/1=1 if you square both sides of cos(0)=1 you get still cos^2(0)=1 so sec^2(0)=1 \[(f^{1})'(3)=\frac{1}{f'(0)}=\frac{1}{0+\frac{\pi}{2}[1]^2}=\frac{1}{\frac{\pi}{2}}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.31/(a/b) means just flip the number in the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks man, or girl?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just made an algebra error

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got it now, but this problem is a pain in the behind

freckles
 one year ago
Best ResponseYou've already chosen the best response.3I might be a she. And also it gets way more fun with more practice.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think my algebra is rusty

freckles
 one year ago
Best ResponseYou've already chosen the best response.3it seems like everyone is working out their algebra kinks in calculus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Any one out there who can give me a hand doing integrals

freckles
 one year ago
Best ResponseYou've already chosen the best response.3post a new question so people can see it :)
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