## anonymous one year ago Solve x2- 5x + 6 = 0 using the quadratic formula.

1. pooja195

2. Nnesha

$\huge\rm \frac{ - b \pm \sqrt{b^2 -4ac} }{ 2a }$ quadratic formula where abc values are $\huge\rm Ax^2 +Bx+C=0$

3. anonymous

?

4. nuttyliaczar

Imagine your equation is in the form Ax^2+Bx+C=0. What is your A, B, and C?

5. pooja195

What are the A B C values

6. nuttyliaczar

Also sometimes you would have to manipulate your equation to get it in that form but in this case it's set up nicely for you

7. anonymous

a=1 b=5 and c=6

8. pooja195

hmm a=1 b= -5 c=6

9. anonymous

cant i do x^2 +2x + 3x -5?

10. pooja195

LEts stick to this its less complicated

11. pooja195

$\huge~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$

12. pooja195

fimiliar with this?

13. anonymous

x2- 5x + 6 = 0 x^2 - 2 + 3 + 6 (x^2-2x) (3x+6) divide by x and 2 so....

14. anonymous

yes

15. pooja195

16. pooja195

$\huge~x=\frac{ -(-5) \pm \sqrt{(-5)^2-4(1)(6)} }{ 2(1) }$

17. pooja195

simplyfy this

18. anonymous

So the x2 can be written as 2x because they are communitive terms. Since the 2x and 5x are like terms, they can combine so 2x-5x = -3x. Ok. Now, since u want to use quadratic u need to assign an a b and c value. The a value is the coefficient of an x^2 in a quadratic equation. Since u don't have a quadratic equation, the coefficient is 0. So the a value is zero. The b value is the -3 and the c value is the number without an x (I don't remember what it was.) Plug the a, b and c values into the quadratic equation and solve. I hope that helps, because i am not good at explaining things. If u still don't understand, I'm sure Kahn academy has a video on it

19. anonymous

$5\pm/2 \sqrt{-6}$

20. anonymous

Oh. I got all the numbers wrong...

21. anonymous

Very sorry

22. pooja195

$\frac{ 5\pm \sqrt{1} }{ 2 }$

23. pooja195

simplfy

24. pooja195

Set up 2 equations

25. anonymous

$5\pm 1/2$

26. anonymous

oh

27. anonymous

The equation is 5+-(5^2 -4(1)(6))^1/2 /2(1). ^1/2 means square root

28. anonymous

jpro, can u stop talking

29. pooja195

thats what i have above xD $\frac{ 5+\sqrt{1} }{ 2}$ $\frac{ 5-\sqrt{1} }{ 2}$ I did this because we have a plus and minus sign so we need 2 seperate equations

30. anonymous

so + that and - that

31. pooja195

yea :)

32. anonymous

33. anonymous

x = 2 and x = 3 x = - 4 and x = - 3 x = 5 and x = - 3 x = - 2 and x = 4

34. anonymous

3 and 2

35. pooja195

yep :)

36. pooja195

Thats right good job :)

37. anonymous

i learned this along time ago the fist thing i learned, but what im doing now has nothing to with it...

38. pooja195

lol what are you learning right now ?

39. anonymous

things like x^2 +6=180

40. pooja195

Oh so like factoring?

41. pooja195

Let me know if you need any help :)

42. pooja195

$$\huge\color{orange}{Welcome~To~OpenStudy}$$ Hey there!!! Since you are new here, read this legendary tutorial for new OpenStudiers!! http://goo.gl/5pp1u0 For an visual tutorial look at this! Its amazing :o https://prezi.com/fs3hqdpcopic/an-unofficial-guide-to-openstudy/ Also consider reading the CoC and the T&C http://openstudy.com/code-of-conduct http://openstudy.com/terms-and-conditions

43. anonymous

not really were r kinda using a diffent methon with squareroots

44. pooja195

oh right thats what its called :)