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anonymous

  • one year ago

Solve x2- 5x + 6 = 0 using the quadratic formula.

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  1. pooja195
    • one year ago
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    List your abc values

  2. Nnesha
    • one year ago
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    \[\huge\rm \frac{ - b \pm \sqrt{b^2 -4ac} }{ 2a }\] quadratic formula where abc values are \[\huge\rm Ax^2 +Bx+C=0\]

  3. anonymous
    • one year ago
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    ?

  4. nuttyliaczar
    • one year ago
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    Imagine your equation is in the form Ax^2+Bx+C=0. What is your A, B, and C?

  5. pooja195
    • one year ago
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    What are the A B C values

  6. nuttyliaczar
    • one year ago
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    Also sometimes you would have to manipulate your equation to get it in that form but in this case it's set up nicely for you

  7. anonymous
    • one year ago
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    a=1 b=5 and c=6

  8. pooja195
    • one year ago
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    hmm a=1 b= -5 c=6

  9. anonymous
    • one year ago
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    cant i do x^2 +2x + 3x -5?

  10. pooja195
    • one year ago
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    LEts stick to this its less complicated

  11. pooja195
    • one year ago
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    \[\huge~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \]

  12. pooja195
    • one year ago
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    fimiliar with this?

  13. anonymous
    • one year ago
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    x2- 5x + 6 = 0 x^2 - 2 + 3 + 6 (x^2-2x) (3x+6) divide by x and 2 so....

  14. anonymous
    • one year ago
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    yes

  15. pooja195
    • one year ago
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    By factoring? Its asking to use the quadratic formula .

  16. pooja195
    • one year ago
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    \[\huge~x=\frac{ -(-5) \pm \sqrt{(-5)^2-4(1)(6)} }{ 2(1) } \]

  17. pooja195
    • one year ago
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    simplyfy this

  18. anonymous
    • one year ago
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    So the x2 can be written as 2x because they are communitive terms. Since the 2x and 5x are like terms, they can combine so 2x-5x = -3x. Ok. Now, since u want to use quadratic u need to assign an a b and c value. The a value is the coefficient of an x^2 in a quadratic equation. Since u don't have a quadratic equation, the coefficient is 0. So the a value is zero. The b value is the -3 and the c value is the number without an x (I don't remember what it was.) Plug the a, b and c values into the quadratic equation and solve. I hope that helps, because i am not good at explaining things. If u still don't understand, I'm sure Kahn academy has a video on it

  19. anonymous
    • one year ago
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    \[5\pm/2 \sqrt{-6}\]

  20. anonymous
    • one year ago
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    Oh. I got all the numbers wrong...

  21. anonymous
    • one year ago
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    Very sorry

  22. pooja195
    • one year ago
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    \[\frac{ 5\pm \sqrt{1} }{ 2 }\]

  23. pooja195
    • one year ago
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    simplfy

  24. pooja195
    • one year ago
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    Set up 2 equations

  25. anonymous
    • one year ago
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    \[5\pm 1/2\]

  26. anonymous
    • one year ago
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    oh

  27. anonymous
    • one year ago
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    The equation is 5+-(5^2 -4(1)(6))^1/2 /2(1). ^1/2 means square root

  28. anonymous
    • one year ago
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    jpro, can u stop talking

  29. pooja195
    • one year ago
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    thats what i have above xD \[\frac{ 5+\sqrt{1} }{ 2}\] \[\frac{ 5-\sqrt{1} }{ 2}\] I did this because we have a plus and minus sign so we need 2 seperate equations

  30. anonymous
    • one year ago
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    so + that and - that

  31. pooja195
    • one year ago
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    yea :)

  32. anonymous
    • one year ago
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    is that the answer?

  33. anonymous
    • one year ago
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    x = 2 and x = 3 x = - 4 and x = - 3 x = 5 and x = - 3 x = - 2 and x = 4

  34. anonymous
    • one year ago
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    3 and 2

  35. pooja195
    • one year ago
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    yep :)

  36. pooja195
    • one year ago
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    Thats right good job :)

  37. anonymous
    • one year ago
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    i learned this along time ago the fist thing i learned, but what im doing now has nothing to with it...

  38. pooja195
    • one year ago
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    lol what are you learning right now ?

  39. anonymous
    • one year ago
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    things like x^2 +6=180

  40. pooja195
    • one year ago
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    Oh so like factoring?

  41. pooja195
    • one year ago
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    Let me know if you need any help :)

  42. pooja195
    • one year ago
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    \(\huge\color{orange}{Welcome~To~OpenStudy}\) Hey there!!! Since you are new here, read this legendary tutorial for new OpenStudiers!! http://goo.gl/5pp1u0 For an visual tutorial look at this! Its amazing :o https://prezi.com/fs3hqdpcopic/an-unofficial-guide-to-openstudy/ Also consider reading the CoC and the T&C http://openstudy.com/code-of-conduct http://openstudy.com/terms-and-conditions

  43. anonymous
    • one year ago
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    not really were r kinda using a diffent methon with squareroots

  44. pooja195
    • one year ago
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    oh right thats what its called :)

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