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anonymous

  • one year ago

A baseball player has been improving every season since making it to the big leagues. Below is a table of the runs he has scored. His manager wants to try to determine when he will score 243 runs. Explain how to create the exponential function that represents his run-scoring abilities. Then explain how to convert this function into a logarithmic function and why this can help the manager answer his question.

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  1. anonymous
    • one year ago
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    |dw:1433630314852:dw|

  2. anonymous
    • one year ago
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    @jim_thompson5910 can you help?

  3. anonymous
    • one year ago
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    @Concentrationalizing can you?

  4. anonymous
    • one year ago
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    Well, a general exponential function would look like \(a^{x}\). Given that, let's see if we can try and determined what our a-value would be based on the chart you have. The season will represent x-values and the runs will represent y-values. So if we plug those values in: \(a^{1} = 3\) \(a^{2} = 9\) \(a^{3} = 27\) So what would a be?

  5. anonymous
    • one year ago
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    a would be 3, right?

  6. anonymous
    • one year ago
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    Right. So we can say our function is \(y = a^{x}\). Now do you know how to change an exponential equation into a logarithmic one?

  7. anonymous
    • one year ago
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    No I don't

  8. anonymous
    • one year ago
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    Okay. Let's use this idea then. \(log_{b}m = x \implies\ b^{x} = m\) Maybe you've seen that connection between exponentials and logarithms before.

  9. anonymous
    • one year ago
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    Either way, you can kind of see how the variables in that identity switch around when you want to change from a logarithm to an exponential and vice-versa

  10. anonymous
    • one year ago
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    So in the logarithm would b be 3?

  11. anonymous
    • one year ago
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    Correct

  12. anonymous
    • one year ago
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    And then you could say y would take the place of m, so that would give you \(log_{3}y = x\)

  13. anonymous
    • one year ago
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    So the identity above would be your explanation as to why you can claim that this logarithmic function works. As for funding your answer, that comes down to solving for x in the equation \(3^{x} = 243\)

  14. anonymous
    • one year ago
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    x would be 5\[3^{5}=243\]

  15. anonymous
    • one year ago
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    Yep, so 5 seasons to score 243 runs.

  16. anonymous
    • one year ago
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    Okay, I think I understand now. Thank you :)

  17. anonymous
    • one year ago
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    No problem :)

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