anonymous
  • anonymous
what is the distance between (7,1) and (-4,-5)? A. 3 square root of 3 B. square root of 137 C. square root of 157 D. 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Nnesha
  • Nnesha
\[\huge\rm \sqrt{(x_2 -x_1)^2+(y_2 -y_1)^2}\] formula to find distance x and y values are \[\huge\rm (x_1 ,y_1)(x_2 ,y_2)\] substitute x and y values :-)
anonymous
  • anonymous
i got 5 is that wrong?
Nnesha
  • Nnesha
yes that's wrong how did you get 5 ?

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anonymous
  • anonymous
idk lol
Nnesha
  • Nnesha
just substitute numbers instead guessing :(
anonymous
  • anonymous
i did. im honestly not sure how to do it. didnt really understand this lesson in class.
Nnesha
  • Nnesha
alright list x and y values x_1 = ? x_2 = ? y_1 =? y_2 = ?
anonymous
  • anonymous
oh i got square root of 157 now. but what about the secound part how do i do that?
Nnesha
  • Nnesha
2nd part ?
anonymous
  • anonymous
yea like how you had (x1,y1) and (x2,y2)
anonymous
  • anonymous
or is that supposed to be the final answer?
Nnesha
  • Nnesha
x and y values are in order pair x_1 meaning first x X_2 2nd x
Nnesha
  • Nnesha
|dw:1433633191206:dw|
anonymous
  • anonymous
yea thats what i did and got sqaure root of 157
Nnesha
  • Nnesha
okay.
anonymous
  • anonymous
oh my bad that was the first part i got 157 but idk what you are doing in that secound part? is that the answer or do i do more and get another answer?
Nnesha
  • Nnesha
how did you get 157 ?
Nnesha
  • Nnesha
square root of 157***?
anonymous
  • anonymous
|dw:1433633369848:dw|
Nnesha
  • Nnesha
yep right that's it factor of 157 is just one so final answer is square root of 157 :-) nice
Nnesha
  • Nnesha
wait
anonymous
  • anonymous
okay thankyou
anonymous
  • anonymous
its not right?
Nnesha
  • Nnesha
|dw:1433633599820:dw| -5-1 it's not -5--1 bec negative times negative = positive so it becomes -5+1 which is not correct
Nnesha
  • Nnesha
|dw:1433633663476:dw|
anonymous
  • anonymous
okay thankyou
Nnesha
  • Nnesha
np

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