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anonymous

  • one year ago

A bag of 29 tulip bulbs contains 10 red tulip bulbs, 11 yellow tulip bulbs, and 8 purple tulip bulbs. What is the probability that two randomly selected tulip bulbs are both red? What is the probability that the first bulb selected is red and the second is yellow? What is the probability that the first bulb selected is yellow and the second is red?

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  1. anonymous
    • one year ago
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    @nechirwan

  2. anonymous
    • one year ago
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    @sasogeek

  3. KendrickLamar2014
    • one year ago
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    Probability first bulb is red = 14/29 There are not 13 red bulbs left and 28 total bulbs left Probability second bulb is red = 13/28 p = 14/29 * 13/28 = 13/58 = 0.224 2) Probability first bulb is red = 14/29 Probability second bulb is yellow = 8/28 p = 14/29 * 8/28 = 4/29 = 0.138 3) Probability first bulb is yellow = 8/29 Probability second bulb is red = 14/28 p = 8/29 * 14/28 = 4/29 = 0.138

  4. sasogeek
    • one year ago
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    @KendrickLamar2014 where's the 14/29 from?

  5. KendrickLamar2014
    • one year ago
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    14+8+7 = 29

  6. sasogeek
    • one year ago
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    it's 10 red, 11 yellow and 8 purple... did you read the question?

  7. anonymous
    • one year ago
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    I need the probability for both bulbs being red :/

  8. KendrickLamar2014
    • one year ago
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    Whoops, OS was lagging

  9. sasogeek
    • one year ago
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    probability of first bulb being red is 10/29... if that one is taken out, you have 28 bulbs left total and 9 red bulbs left, probability of second ball being red is 9/28. since it's first AND second bulb being red, you have 10/29 * 9/28 = probability of both being red

  10. sasogeek
    • one year ago
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    bulb*

  11. sasogeek
    • one year ago
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    do you understand?

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