## Destinyyyy one year ago Graph the following region-- 2x-5y>=0

1. anonymous

Ignoring the idea of regions, would you know how to graph 2x-5y = 0 as a line?

2. anonymous

No.. I could if zero was another number. I have no examples for this kind of problem

3. anonymous

The fact that the other number is 0 actually just means that you have a y-intersect of 0. Are you familiar with slope-intercept form?

4. anonymous

Yes

5. anonymous

Alright. So if I were to put your inequality into slope-intercept form I would have: $$2x - 5y \ge\ 0$$ $$2x \ge\ 5y$$ $$\frac{2}{5}x \ge\ y$$ So that it maybe looks in a better order, let's rewrite this as $$y \le\ \frac{2}{5}x$$ Now, you know slope-intercept form is $$y = mx+b$$ where m is the slope and b is the y-intercept. So here we have a slope of 2/5, but no value for b. This means that the y-intercept is 0. So with that information, we can graph this line. Would you be able to graph it given the info above?

6. anonymous

Graph just the line I mean, don't worry about the region part yet.

7. anonymous

Yes?

8. anonymous

Just making sure :) Well, if we start from the y-intercept of 0 and use a slope of 2/5, we can get this line: |dw:1433634764962:dw| So how the line is drawn makes sense?

9. anonymous

Yes!

10. anonymous

Okay, so now the region part. So when the inequality says $$y \le\ \frac{2}{5}x$$, it's saying that the correct y-values must be less than or equal to the line. As in the region we want are all the y-values on the line and under the line, meaning we would have this: |dw:1433634956029:dw| So basically, once you put a line into slope-intercept form, if you have $$y \le$$ , you're graphing everything under the line and if you have $$y \ge$$, you're graphing everything above the line.

11. anonymous

Okay. Thank you!

12. anonymous

You're welcome

13. anonymous

Im removing the metal. The answer you gave me was incorrect. @Concentrationalizing

14. anonymous

I dont see how. This is the plot of the graph http://www.wolframalpha.com/input/?i=2x-5y+%3E%3D0 @Destinyyyy

15. anonymous

This is what the question says is the answer

16. anonymous

The correct answer is how I graphed it above. The slope is 2/5, so every point is up 2 and right 5 from the previous point. The way you graphed the line in the screenshot is with a slope of 5/2. But I gave the correct graph.

17. anonymous

The first graph is the correct answer the second is my answer (what you gave me).

18. anonymous

Right, and that first graph is what I gave you. I'm not sure where you're seeing that my graph is the graph on the right of your screenshot. |dw:1433636211206:dw| Those are the points on my graph and the points on the graph marked as correct on your screenshot.

19. anonymous

My apologies I wrote it on my paper wrong.

20. anonymous

I see. I don't mind being wrong and corrected when I am wrong, but as long as you get the correct answer and understand it, then that's what matters. Sorry if there was any confusion.