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anonymous

  • one year ago

anyone who can answer this? a point moves on the parabola y^2=8 in such a way that the rate of change of the ordinate is always 5 units/second. how fast is the abscissa changing when the ordinate is 4?

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  1. ganeshie8
    • one year ago
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    ordinate : y coordinate abscissa : x coordinate

  2. ganeshie8
    • one year ago
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    could you double check the equation of parabola, is it really `y^2=8` ?

  3. anonymous
    • one year ago
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    yes it is y^2=8

  4. anonymous
    • one year ago
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    i also think that the questions seems lacking, or something wrong?

  5. ganeshie8
    • one year ago
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    im pretty sure the equation is y^2=8\(\color{red}{x}\)

  6. ganeshie8
    • one year ago
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    y^2 = 8 does not produce a parabola when you graph

  7. anonymous
    • one year ago
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    yes..

  8. anonymous
    • one year ago
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    i also think that way..

  9. ganeshie8
    • one year ago
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    good, lets make it y^2=8x

  10. ganeshie8
    • one year ago
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    we're given \(\dfrac{dy}{dt}=5\)

  11. ganeshie8
    • one year ago
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    \[y^2=8x\] differentiate both sides with respect to \(t\)

  12. anonymous
    • one year ago
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    \[2y \frac{ dy }{ dt} = 8\frac{ dx }{ dt }\]

  13. anonymous
    • one year ago
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    is that right?

  14. ganeshie8
    • one year ago
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    Yes, plugin the given values

  15. anonymous
    • one year ago
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    i got it

  16. anonymous
    • one year ago
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    \[\frac{ dx }{ dt} = 5\]

  17. anonymous
    • one year ago
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    thanks sir

  18. ganeshie8
    • one year ago
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    Yw!

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