anonymous
  • anonymous
anyone who can answer this? a point moves on the parabola y^2=8 in such a way that the rate of change of the ordinate is always 5 units/second. how fast is the abscissa changing when the ordinate is 4?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ganeshie8
  • ganeshie8
ordinate : y coordinate abscissa : x coordinate
ganeshie8
  • ganeshie8
could you double check the equation of parabola, is it really `y^2=8` ?
anonymous
  • anonymous
yes it is y^2=8

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anonymous
  • anonymous
i also think that the questions seems lacking, or something wrong?
ganeshie8
  • ganeshie8
im pretty sure the equation is y^2=8\(\color{red}{x}\)
ganeshie8
  • ganeshie8
y^2 = 8 does not produce a parabola when you graph
anonymous
  • anonymous
yes..
anonymous
  • anonymous
i also think that way..
ganeshie8
  • ganeshie8
good, lets make it y^2=8x
ganeshie8
  • ganeshie8
we're given \(\dfrac{dy}{dt}=5\)
ganeshie8
  • ganeshie8
\[y^2=8x\] differentiate both sides with respect to \(t\)
anonymous
  • anonymous
\[2y \frac{ dy }{ dt} = 8\frac{ dx }{ dt }\]
anonymous
  • anonymous
is that right?
ganeshie8
  • ganeshie8
Yes, plugin the given values
anonymous
  • anonymous
i got it
anonymous
  • anonymous
\[\frac{ dx }{ dt} = 5\]
anonymous
  • anonymous
thanks sir
ganeshie8
  • ganeshie8
Yw!

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