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anonymous
 one year ago
does 1/2sin^2x= 1/4 cos(2x)
anonymous
 one year ago
does 1/2sin^2x= 1/4 cos(2x)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Expand out both sides to see if that's true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not sure if I know how to do that..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cos(2x)=cos(x+x). now tell me how to expand the right hand side?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02sin(x)^2=cos(2x) cos(2X)=12sin^2x so.. 2sin(x)^2=2sin(x)^21 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, actually. you're done!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, you arrived at a contradiction and it can't be true.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?} cosxsinx dx\] = which one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0integral of cosx * sinx dx I got the 1/2 sin^2(x) but my answer key I have the other one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433648150311:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433648346891:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0anyone? am I doing my Usub wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's correct as far as I am concerned, the only thing missing is the Constant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then 1/2 sin^2x should = 1/4 cos(2x) ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In a question like this, aren't we proving that LHS = RHS, how did you resort to using integration?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the question was the integration. What I got was the 1/2 sin^2 (x) and my prof answer key shows the 1/4 cos (2x) wondering who made the mistake of if they are the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433649465541:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well \(cos(2x) = 12sin^{2}x\) So \(\frac{1}{4}cos(2x) = \frac{1}{4}(12sin^{2}x) =\frac{1}{4} + \frac{1}{2}sin^{2}x\) But keep in mind that we have that constant of integration, the +C. That plus C would absorb the 1/4 and leave us with simply \(\frac{1}{2}sin^{2}x + C\) Your answer is equivalent as far as Im concerned.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK Thank you Concentrating!
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