A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

what type of equation is this ? Need helps please to identify

  • This Question is Open
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[0=50000x ^{3}-2700x ^{2}+10x\] when solving for x

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it's a cubic. Since it has no constant term one of the solutions is simply x = 0 Now you can divide the equation by x and solve the quadratic equation which results using the quadratic formula. Can you do that?

  3. radar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Is that really permissible? Know that x can be 0, yet you divide by x, isn't division by zero undefined?

  4. radar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Probably meant to say factor the equation such that it looks like this: 10x(20x -1)(250x -1 ) = 0 Now divide both sides by 10 getting: x(20x - 1)(250x - 1) = 0 Now solve.

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You don't divide by zero in any way and there's no need to factor anything. The reason why x = 0 is due to the fact that we can rewrite that equation as: 0*x^3 + 0*x^2 + 0*x+0 = 50000*x^3 + 2700*x^2+10*x^1+0*x The way expressions are equated when dealing with powers of x is by equating each power individually. That's how we have: 0*x^3=50000*x^3. Since 0 can\t be 50000 the only solution to this is 0. Same goes for everything else.

  6. radar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I dont, the message was directed to @JackJordan

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks everyone for your help, big help with my maths work :D

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Quick question @radar would it be possible at 10x(20x -1)(250x -1 ) = 0 i divide by 10x instead of just 10 getting (20x - 1)(250x - 1) = 0 then just equating both to zero getting x= 20, x= 250 because i am not sure how to solve 10(20x - 1)(250x - 1) = 0

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh wait never mind i got it, x(20x - 1)(250x - 1) = 0 i will equate all three terms to zero then i don't have to divide x by zero like you said above(and it has three answers like it should) so x=0,x=20,x=250

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.