anonymous
  • anonymous
what type of equation is this ? Need helps please to identify
Physics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[0=50000x ^{3}-2700x ^{2}+10x\] when solving for x
anonymous
  • anonymous
it's a cubic. Since it has no constant term one of the solutions is simply x = 0 Now you can divide the equation by x and solve the quadratic equation which results using the quadratic formula. Can you do that?
radar
  • radar
Is that really permissible? Know that x can be 0, yet you divide by x, isn't division by zero undefined?

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radar
  • radar
Probably meant to say factor the equation such that it looks like this: 10x(20x -1)(250x -1 ) = 0 Now divide both sides by 10 getting: x(20x - 1)(250x - 1) = 0 Now solve.
anonymous
  • anonymous
You don't divide by zero in any way and there's no need to factor anything. The reason why x = 0 is due to the fact that we can rewrite that equation as: 0*x^3 + 0*x^2 + 0*x+0 = 50000*x^3 + 2700*x^2+10*x^1+0*x The way expressions are equated when dealing with powers of x is by equating each power individually. That's how we have: 0*x^3=50000*x^3. Since 0 can\t be 50000 the only solution to this is 0. Same goes for everything else.
radar
  • radar
I dont, the message was directed to @JackJordan
anonymous
  • anonymous
Thanks everyone for your help, big help with my maths work :D
anonymous
  • anonymous
Quick question @radar would it be possible at 10x(20x -1)(250x -1 ) = 0 i divide by 10x instead of just 10 getting (20x - 1)(250x - 1) = 0 then just equating both to zero getting x= 20, x= 250 because i am not sure how to solve 10(20x - 1)(250x - 1) = 0
anonymous
  • anonymous
oh wait never mind i got it, x(20x - 1)(250x - 1) = 0 i will equate all three terms to zero then i don't have to divide x by zero like you said above(and it has three answers like it should) so x=0,x=20,x=250

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