anonymous
  • anonymous
a point moves on the parabola y^2=8 in such a way that the rate of change of the ordinate is always 5 units/second. how fast is the abscissa changing when the ordinate is 4?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Thanks you for showing up D:
BAdhi
  • BAdhi
shouldnt there be an x term in the parabola?
anonymous
  • anonymous
Oh yea

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BAdhi
  • BAdhi
so in general what you should do is differentiate the equation wrt to time. For example if the equation is \(x = f(y)\) \[\frac {dx}{dt} = \frac{df(y)}{dt}\] which further can be represented as, \[\frac{dx}{dt} = \frac{df(y)}{dy}\frac{dy}{dt}\] so when \(y=4\) find the \(\frac{dx}{dt}\) \[\left[\frac{dx}{dt} \right]_{y=4} = \left[\frac{df(y)}{dy}\right]_{y=4} \left[\frac{dy}{dt}\right]_{y=4} \]
anonymous
  • anonymous
okay, so I have to find that?
BAdhi
  • BAdhi
yeah find the values of the expressions in the r.h.s
anonymous
  • anonymous
kk one second
anonymous
  • anonymous
\[ \frac{ ds }{ dt }=5?\]
BAdhi
  • BAdhi
but according to your given problem, the question itself contradicts. since it is stated that \(y^2=8\implies y = \pm \sqrt 8\) which is a constant and later it talks about a rate of change in the value of y wrt time.. Can you state the equation correctly
anonymous
  • anonymous
I have no clue about this :/
BAdhi
  • BAdhi
are you sure that the question given to is like that?
anonymous
  • anonymous
I think i may be able to figure it out, but thank you soooo much man! :D
anonymous
  • anonymous
medal for you ;)
BAdhi
  • BAdhi
u are welcome ;)
anonymous
  • anonymous
=D

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