anonymous
  • anonymous
sin(a) _______ = 1/2 [sin(a+b) + sin(a-b)] a) sin(b) b) cos(a) c) cos(b) d) sin(a)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
hartnn
  • hartnn
can you expand sin (a+b) and sin(a-b) ? know the formulas?
anonymous
  • anonymous
no..haha

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hartnn
  • hartnn
ok, here you go! \(\Large \sin (a+b) = \sin a \cos b +\cos a \sin b\) \(\Large \sin (a-b) = \sin a \cos b -\cos a \sin b\) just plug these in, on the right side.
hartnn
  • hartnn
like add them and see what u get...
hartnn
  • hartnn
anything getting cancelld out ?
anonymous
  • anonymous
idk why but i couldn't get anything from it
hartnn
  • hartnn
did you add? \(\Large \sin (a+b) + \Large \sin (a-b) \\ \Large = \sin a \cos b +\cos a \sin b+ \sin a \cos b -\cos a \sin b\) now you see any term getting cancelled out ?
anonymous
  • anonymous
So when you add them, the latter terms cancel. You will be left with two lots of sin(a)cos(b) Now dividing by two, what do we get?
anonymous
  • anonymous
so is it cos (b)?
hartnn
  • hartnn
jack buddy! let him/her do something :P
hartnn
  • hartnn
yep, sin a cos b so yeah
anonymous
  • anonymous
hrtnn why'd you give him the answer? He thought it was cos b
hartnn
  • hartnn
we all know who gave out the answer, so cut it out lol

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