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anonymous

  • one year ago

if tanø= -4/3 in quadrant II, what is cosø?

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  1. anonymous
    • one year ago
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    @hartnn

  2. freckles
    • one year ago
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    hi! we can draw a right triangle in quadrant 2 .

  3. freckles
    • one year ago
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    or if you want @hartnn I will step away

  4. hartnn
    • one year ago
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    no please, go ahead!

  5. anonymous
    • one year ago
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    anyone that can help me is fine:)

  6. freckles
    • one year ago
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    |dw:1433661088760:dw|

  7. freckles
    • one year ago
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    this is what the triangle looks like with the given info

  8. freckles
    • one year ago
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    to find cos(theta) you need to know the adjacent side (this is given) and the hyp

  9. anonymous
    • one year ago
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    adjacent is on the -3, right?

  10. freckles
    • one year ago
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    yes sir

  11. anonymous
    • one year ago
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    so whats next

  12. freckles
    • one year ago
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    you need the find the hyp

  13. freckles
    • one year ago
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    |dw:1433661364938:dw| this length that I just drew in black

  14. freckles
    • one year ago
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    hint: think Pythagorean theorem

  15. anonymous
    • one year ago
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    so 5

  16. freckles
    • one year ago
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    yep yep

  17. freckles
    • one year ago
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    and recall cos(theta)=adj/hyp

  18. anonymous
    • one year ago
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    so what do i do with that equation?

  19. freckles
    • one year ago
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    plug in the values

  20. freckles
    • one year ago
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    adj=-3 you said hyp=5 you said

  21. anonymous
    • one year ago
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    sp 3/5 is the answer? that simple???:D

  22. anonymous
    • one year ago
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    so*

  23. freckles
    • one year ago
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    well -3/5

  24. freckles
    • one year ago
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    yes

  25. anonymous
    • one year ago
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    oh right

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