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imqwerty
 one year ago
By the reaction of of carbon & oxygen , a mixture of co & co2 is obtained. What is the composition by mass of the mixture obtained when 20grams of O2 reacts with 12grams of carbon??
imqwerty
 one year ago
By the reaction of of carbon & oxygen , a mixture of co & co2 is obtained. What is the composition by mass of the mixture obtained when 20grams of O2 reacts with 12grams of carbon??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have the chemical formula for this reaction?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.04C + 3O2 > 2CO2 + 2CO

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So first you need to convert 20g of O2 into moles.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And then the 12g of C into moles.

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0we get 1mole of C reacting with 0.625 moles of O2

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0i think that the limitating reagent concept apply here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how the calculation works?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.01st i got the limitating reagent as O2 2nd  according to the equation 3 moles of O2 give 2moles of CO2 and 2 moles of CO. 3rd  we have 20/32 moles of O2 so we will get 5/12 moles of both co and co2 4th  we have the moles of co and co2 nw we calculate their mass 5th  mass of co = 35/3gm and mass of co2 = 55/3 6th mass of co2:mass of co = 11:7 but the answer given is 21:11

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you get that ratio?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0mass of co2/mass of co = 55/3 x 3/35 =11:7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It seems like what your doing is right, and that answer doesn't seem to be right to me, as they got 21g for CO2 nO2 = m/M = 20g/32g/mol = 0.625mol nCO2 = nO2 x 2/3 = 0.41667 mol mCO2 = M x m = 0.41667 mol x 44.01g/mol = 18.333 g = 55/3 They used the mass of O2 needed rather than the actual mass.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My ratio 18.338967/11.671767 ~ 1.5714 thats almost the same as 11/7 = 1.5714 So its correct to me, but then again maybe u should double check with your teacher as to why the answer is different.

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0thanks @ShizukaTheOtaku
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