LynFran
  • LynFran
tan(1/2(cos^−1(x))=√1−x/1+x
Trigonometry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Do you have any idea on starting this question?
LynFran
  • LynFran
no is say prove that their equal
anonymous
  • anonymous
Well that's the first step :) Do you know what to do next?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

LynFran
  • LynFran
no
anonymous
  • anonymous
We don't need to rush in and do everything in one go :) We can firstly start of with: tan(1/2(cos^−1(x))
anonymous
  • anonymous
Tan ( 1 ) 2 Cos^-1(x)
anonymous
  • anonymous
Try changing the inverse trig ratio
anonymous
  • anonymous
You get something like: Tan (Secx) 2
LynFran
  • LynFran
ok
anonymous
  • anonymous
So graphically, it looks something like this
anonymous
  • anonymous
|dw:1433678743148:dw|
anonymous
  • anonymous
The only way to get the prove this, is by using properties of Pythagoras's, since we are dealing with a right angle triangle
LynFran
  • LynFran
ok so we finding the hypotenuse in other word?
anonymous
  • anonymous
Yeah we could try to find the hypotenuse or the other side. Just some way to get us that Square root, to help us prove that LHS = RHS
LynFran
  • LynFran
so we would have x^2=(1/cosx)^2+2^2)?
Loser66
  • Loser66
Question: \(tan (\dfrac{1}{2} arccos (x))\) or \(tan (\dfrac{1}{2arccos (x))}\). which one?
LynFran
  • LynFran
tan(12arccos(x))
LynFran
  • LynFran
the first 1
Loser66
  • Loser66
if so, then the right hand side must be \(\dfrac{\sqrt {1-x^2}}{1+x}\) , right?
Loser66
  • Loser66
you missed the square at x from numerator. Am I right? please check the problem
Loser66
  • Loser66
|dw:1433681866420:dw|
LynFran
  • LynFran
the right side has no square at x its just; the root of (1-x)/(1+x)
Loser66
  • Loser66
If it is so, I failed. :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.