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anonymous
 one year ago
Antons family drove 216 miles to the lake averaging 48mi/hr. On the return trip home they averaged 54mi/hr.
What was the total time that Antons family took driving to and from the Lake?
A. 8hrs
B. 8.5hrs
C. 9hrs
D. 9.5hrs
anonymous
 one year ago
Antons family drove 216 miles to the lake averaging 48mi/hr. On the return trip home they averaged 54mi/hr. What was the total time that Antons family took driving to and from the Lake? A. 8hrs B. 8.5hrs C. 9hrs D. 9.5hrs

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 @shadow13

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Each part of the trip is 216 miles. The first part is 216 miles at 48 mph. The second part is 216 miles at 54 mph. With speed questions, always start with the basic speed equation. Speed is the rate of distance per time. \(speed = \dfrac{distance}{time} \) Using s = speed, d = distance, and t = time, we can write: \(s = \dfrac{d}{t} \) Ok so far?

shadow13
 one year ago
Best ResponseYou've already chosen the best response.0this is what i got for the going: 48 miles takes 1 hr 216 miles takes x hr x = 216*1/48 = 4.5 hr for the return: 54 miles takes 1 hr 216 miles take 216*1/54 = 4 hr so the total time is 9.5 hr

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Since the question is asking for a time, we take the basic speed equation, and we solve for time. \(s = \dfrac{d}{t} \) \(st = d\) \(t = \dfrac{d}{s} \) Now we have an equation for time. Time is distance divided buy average speed. With this equation, you can use the info of each half of the trip and find its time. then add the two times together.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0First part: \(t = \dfrac{d}{s} = \dfrac{216~miles}{48 \frac{mi}{h}} = 4.5 ~h\) Second part: \(t = \dfrac{d}{s} = \dfrac{216~miles}{54 \frac{mi}{h}} = 4 ~h\) Total time = 4.5 h + 4 h = 9.5 h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thanks you guys for all of your help @shadow13 @mathstudent55

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0You're welcome. Did you understand how to work the problem?
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