fun question

- imqwerty

fun question

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

ask away

- imqwerty

##### 1 Attachment

- anonymous

0.0 thats alot of lines

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

b

- imqwerty

no

- anonymous

then it has to be c

- anonymous

there no other way at all

- anonymous

too much work.... :-/
looks challenging, maybe later....

- imqwerty

no

- yadu123

how is this fun

- anonymous

i do not know

- anonymous

what level math is this?

- anonymous

9 +10 = 21

- anonymous

ha xD

- imqwerty

10-11th grade

- ParthKohli

This question is just so bad that coordinate geometry seems to be the way to go.

- anonymous

wait you guys still have school

- anonymous

i would probably say d. because it seems like the 2 triangles are similar. so if you divided the larger one by the area of the smaller one you would get 2 because the larger one is double the smaller one.

- anonymous

man down in Florida it's over

- ParthKohli

I was looking at the wrong triangles. Oops.
Yes, they do look like they're similar.

- imqwerty

i'll be posting the solution after i eat 2hot dogs

- anonymous

XD

- anonymous

@Jennjuniper that is a clever observation!

- anonymous

it was all wrong!! it should be \[RS=PS=1\] and \[AQ=AP=\sqrt{2}\]

- imqwerty

shall i tell the solution now??

- mathstudent55

Ratio is 2/1

- imqwerty

ok i'll wait

- imqwerty

thats right @mathstudent55

- mathstudent55

Areas are 0.5 & 0.25

- mathstudent55

Great q. Thanks.

- BAdhi

\[\measuredangle RAS =60 ^\circ \] and since RA = AS, \(\Delta RAS\) is a equilateral triangle
Therefore \[\measuredangle RSP = 30^\circ\] , \(\Delta RSP\) is a isosceles triangle
Guess that information is enough for finding the area of the RSP.
\(AP = AQ = \sqrt{2}\) (considering AFP and ABQ)
\(\measuredangle PAQ = 30^\circ\) since \(\measuredangle FAP = \measuredangle QAB = 45^\circ\)
Guess that is enough to find the area of the APQ

- imqwerty

yes u've told the right areas too @mathstudent55

- imqwerty

well done @BAdhi

- anonymous

great answers both! @mathstudent55 and @BAdhi !!

- BAdhi

Thanks for posting a good question ;)

- imqwerty

i'll keep posting such questions everyday @BAdhi

- imqwerty

solution

##### 1 Attachment

- ganeshie8

Nice!

- ILovePuppiesLol

i like fun questions !!!!!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.