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anonymous

  • one year ago

Medal! Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

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  1. anonymous
    • one year ago
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    \[4m^\frac{ 4 }{ 3 }*m^\frac{ -7 }{ 4 }\]

  2. Nnesha
    • one year ago
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    \[\huge\rm x^m \times x^n = x^{m+n}\] exponent rule! when u multiply same bases you should ad their exponents

  3. anonymous
    • one year ago
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    i don't now how to add the fractions. because they've got different denominators

  4. Nnesha
    • one year ago
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    multiply them

  5. Nnesha
    • one year ago
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    \[\frac{ 4 }{ 3 } + \frac{ -7 }{ 4 } = \frac{ ? }{ 3(4) }\]

  6. anonymous
    • one year ago
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    \[\frac{ -28 }{ 12 }\]

  7. Nnesha
    • one year ago
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    |dw:1433698357618:dw| 4 and 3 are the denominator first fraction doesn't have 4 at the denominator so multiply 4 times 4 2nd fraction -7 doesn't have 3 at the denominator so multiply it by 3 same like cross multiplication but don't forget the signs

  8. anonymous
    • one year ago
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    which equals\[\frac{ 7}{ 3 }\]

  9. anonymous
    • one year ago
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    wait, what?

  10. anonymous
    • one year ago
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    i just realized, because they're exponents, wouldn't i be adding the fractions, not multiplying?

  11. Nnesha
    • one year ago
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    yes add \[\frac{ 4 }{ 3 } \color{Red}{+} \frac{\color{blue}{ -}7 }{ 4 } = \frac{ 4 }{3 } \color{reD}{-}\frac{7}{4}\] here positive times negative = negative now 3 and 4 both are common denominator

  12. Nnesha
    • one year ago
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    the*

  13. Nnesha
    • one year ago
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    yes add \[\frac{ 4 }{ 3 } \color{Red}{+} \frac{\color{blue}{ -}7 }{ 4 } = \frac{ 4 }{3 } \color{reD}{-}\frac{7}{4}=\frac{????}{3(4)}\] now cross multiply don't forget the negative sign |dw:1433698871386:dw|

  14. anonymous
    • one year ago
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    \[\frac{ 28 }{ 12 }\]

  15. anonymous
    • one year ago
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    that's what i got before but that's when you're multiplying it and they need to be added because they're exponents.

  16. Nnesha
    • one year ago
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    how did you get 28?

  17. Nnesha
    • one year ago
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    |dw:1433699227333:dw| or in other words multiply first fraction by 4 and 2nd fraction by 3

  18. Nnesha
    • one year ago
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    \[\frac{ 4 }{ 3 } \color{Red}{+} \frac{\color{blue}{ -}7 }{ 4 } = \frac{ 4 }{3 } \color{reD}{-}\frac{7}{4}= \frac{4(4) - 3(7)}{3(4)}\] like this

  19. anonymous
    • one year ago
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    \[\frac{ 16-21 }{ 12 }\]

  20. anonymous
    • one year ago
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    \[\frac{ -5 }{ 12 }\]

  21. anonymous
    • one year ago
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    like that?

  22. Nnesha
    • one year ago
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    yes that's right so \[\large\rm 4m^\frac{ 4 }{ 3 }*m^\frac{ -7 }{ 4 } = ???\]

  23. anonymous
    • one year ago
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    \[4m^\frac{ -5 }{ 12 }\]

  24. Nnesha
    • one year ago
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    yep right now there is another exponent rules \[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\]

  25. anonymous
    • one year ago
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    yup. got that. thank you!

  26. Nnesha
    • one year ago
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    np :-)

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