anonymous
  • anonymous
Factor using the AC method or Trial and Error. 42k2 + 59k + 20
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what are you sopposed to do
anonymous
  • anonymous
factor the equation
anonymous
  • anonymous
what grade is this?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
its algebra
anonymous
  • anonymous
what grade is this 7th grade?
anonymous
  • anonymous
no im in college
anonymous
  • anonymous
sorry i cant help im in 6th grade sorry
anonymous
  • anonymous
what are the ks for?
anonymous
  • anonymous
change it to (7k+4) * (6k+5)
anonymous
  • anonymous
becuase thats the answer
anonymous
  • anonymous
becuase if you raise the k to the 2 power than ((42*k2) + 59k) + 20 and change it to 42k2+24k+35k+20 than add up the first two terms 6k * (7k+4) and add up the last two terms 5 * (7k+4) than add up the four terms (6k+4) * (7k +4)= (6k +4) * (7k + 4)
anonymous
  • anonymous
hello @BlondeStudent

Looking for something else?

Not the answer you are looking for? Search for more explanations.