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anonymous

  • one year ago

A figure shows a portion of a graph of f(x) = x^2 + 3x + 1 and a rectangle with its base on the x-axis and a vertex on the graph. what is the area of the rectangle? (hint: f(2) is the height) ???

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  1. anonymous
    • one year ago
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    hmm, how do you find the rectangles width?

  2. anonymous
    • one year ago
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    This is all that it says, problem #70

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  3. anonymous
    • one year ago
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    \(f(0.2)\) is the height, not \(f(2)\). The width of the rectangle is the difference between the interval's endpoints: \(0.3-0.2=0.1\). So, the area of the rectangle is \(0.1\times f(0.2)\).

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