anonymous
  • anonymous
QUICK QUESTION need someone who knows statistics
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
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anonymous
  • anonymous
What's the problem here? @Michele_Laino answered your question just fine the first time around.

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anonymous
  • anonymous
I didn't understand the equation.
anonymous
  • anonymous
someone help please
anonymous
  • anonymous
The \(\chi^2\) statistic is given as \[\sum_{i=1}^n\frac{(\text{observed}_i-\text{expected}_i)^2}{\text{expected}_i}\] where \(i\) denotes the category, which in this case is milkshake flavor. There are 3 of these, so \(n=3\). \(\text{observed}_i\) is the recorded value of a given flavor, whereas \(\text{expected}_i\) is the expected value of a given flavor. For example, the parlor finds that \(202\) vanilla milkshakes were ordered, while they expected \(175\) to be ordered. So, the contribution of vanilla shakes to the \(\chi^2\) statistic is \[\frac{(\text{observed}_\text{vanilla}-\text{expected}_\text{vanilla})^2}{\text{expected}_\text{vanilla}}=\frac{(202-175)^2}{175}\] You do the same for the other flavors and add them together. \[\chi^2=\frac{{{{\left( {202 - 175} \right)}^2}}}{{175}} + \frac{{{{\left( {112 - 125} \right)}^2}}}{{125}} + \frac{{{{\left( {269 - 250} \right)}^2}}}{{250}} \]
anonymous
  • anonymous
so from this you get "yes, the x^2 value was too high"?
anonymous
  • anonymous
@SithsAndGiggles
anonymous
  • anonymous
Well that depends on what value of \(\chi^2\) you get \(\chi^2\approx 6.96\). Since \(n=3\), you have \(n-1=2\) degrees of freedom. What \(p\) value do you get for a significance level of \(0.05\) and \(2\) degrees of freedom?
anonymous
  • anonymous
statistics is super not my thing. i hardly understand what you're talking about
anonymous
  • anonymous
@SithsAndGiggles
anonymous
  • anonymous
You'll have to be more precise. What do you not understand? I'll try my best to explain.
anonymous
  • anonymous
i dont understand any of this. is like a foreign language.
anonymous
  • anonymous
@sithsandgiggles
anonymous
  • anonymous
i just need the answer right now @sithsandgiggles
Michele_Laino
  • Michele_Laino
Thanks!! :) @SithsAndGiggles

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