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anonymous
 one year ago
QUICK QUESTION need someone who knows statistics
anonymous
 one year ago
QUICK QUESTION need someone who knows statistics

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What's the problem here? @Michele_Laino answered your question just fine the first time around.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I didn't understand the equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The \(\chi^2\) statistic is given as \[\sum_{i=1}^n\frac{(\text{observed}_i\text{expected}_i)^2}{\text{expected}_i}\] where \(i\) denotes the category, which in this case is milkshake flavor. There are 3 of these, so \(n=3\). \(\text{observed}_i\) is the recorded value of a given flavor, whereas \(\text{expected}_i\) is the expected value of a given flavor. For example, the parlor finds that \(202\) vanilla milkshakes were ordered, while they expected \(175\) to be ordered. So, the contribution of vanilla shakes to the \(\chi^2\) statistic is \[\frac{(\text{observed}_\text{vanilla}\text{expected}_\text{vanilla})^2}{\text{expected}_\text{vanilla}}=\frac{(202175)^2}{175}\] You do the same for the other flavors and add them together. \[\chi^2=\frac{{{{\left( {202  175} \right)}^2}}}{{175}} + \frac{{{{\left( {112  125} \right)}^2}}}{{125}} + \frac{{{{\left( {269  250} \right)}^2}}}{{250}} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so from this you get "yes, the x^2 value was too high"?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well that depends on what value of \(\chi^2\) you get \(\chi^2\approx 6.96\). Since \(n=3\), you have \(n1=2\) degrees of freedom. What \(p\) value do you get for a significance level of \(0.05\) and \(2\) degrees of freedom?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0statistics is super not my thing. i hardly understand what you're talking about

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You'll have to be more precise. What do you not understand? I'll try my best to explain.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand any of this. is like a foreign language.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just need the answer right now @sithsandgiggles

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0Thanks!! :) @SithsAndGiggles
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