Math2400
  • Math2400
True or false....i believe it's false because not both intervals should be included..posting question
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Math2400
  • Math2400
The series \[\sum_{n=1}^{\infty} (-2x)^{n} \] converges on the interval \[\frac{ -1 }{ 2 } < x < \frac{ 1 }{ 2 }\]
Zarkon
  • Zarkon
true
Math2400
  • Math2400
it's not supposed to be |dw:1433703146278:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Zarkon
  • Zarkon
plug in -1/2 what do you get?
Math2400
  • Math2400
1
Zarkon
  • Zarkon
\[\sum_{n=1}^{\infty} (-2(-1/2))^{n}=\sum_{n=1}^{\infty} 1=\infty\]
Math2400
  • Math2400
okkayy i see. Thank you :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.