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anonymous

  • one year ago

Given the functions f(x) = 3x + 2 −4/x and g(x) = 2 − 3x, find the indicated values. a) f(a + b) b) g(a) − g(a − b) + f(a)

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  1. anonymous
    • one year ago
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    replace x in the equation above with (a+b)

  2. anonymous
    • one year ago
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    f(a+b)=3(a+b)+2 -4/(a+b)

  3. xapproachesinfinity
    • one year ago
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    wherever you x replace by a+b \[f(x)=3x+2-\frac{4}{x}\] \[f(\color {red}{a+b})=3(\color{red}{a+b})+2-\frac{4}{\color{red}{a+b}}\]

  4. xapproachesinfinity
    • one year ago
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    if for example f(x)=x^-2 they ask f(c) \[f(\color{blue}{c})=\color{blue}{c}^2-2\] just a matter of replacing the dummy variable

  5. anonymous
    • one year ago
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    whats a+b tho

  6. anonymous
    • one year ago
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    what do i do when i set it up like that

  7. xapproachesinfinity
    • one year ago
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    that's what they asked you the evaluate a+b standards as some variable

  8. xapproachesinfinity
    • one year ago
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    hmm you can simply more if they ask you just depends on the question

  9. xapproachesinfinity
    • one year ago
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    in this case i would just leave it that way

  10. anonymous
    • one year ago
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    what about the second one?

  11. xapproachesinfinity
    • one year ago
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    second you gonna do each one separately g(a) g(a-b) f(a) after that the results do g(a)-g(a-b)+f(a)

  12. xapproachesinfinity
    • one year ago
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    let me see if you can do g(a)

  13. anonymous
    • one year ago
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    i thought were supposed to use the equation they gave us tho

  14. anonymous
    • one year ago
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    i dont know

  15. xapproachesinfinity
    • one year ago
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    what equation?

  16. anonymous
    • one year ago
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    the second part

  17. xapproachesinfinity
    • one year ago
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    you have g(x) right find g(a) by replacing x with a

  18. xapproachesinfinity
    • one year ago
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    i broke it down to steps as you can see first find g(a) then g(a-b) then f(a) all separately

  19. xapproachesinfinity
    • one year ago
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    try to do g(a) first let me see you do it

  20. anonymous
    • one year ago
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    so 2-3(a)?

  21. xapproachesinfinity
    • one year ago
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    yes g(a)=2-3a what about g(a-b) now

  22. xapproachesinfinity
    • one year ago
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    use the same function g(x)=2-3x to find that

  23. anonymous
    • one year ago
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    2-3(a-b)?

  24. xapproachesinfinity
    • one year ago
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    yes good

  25. xapproachesinfinity
    • one year ago
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    now f(a)

  26. anonymous
    • one year ago
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    2-3(a)-2-3(a-b)+3(a)+2-4/(a)?

  27. xapproachesinfinity
    • one year ago
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    that the next step let's not skip do f(a) first

  28. xapproachesinfinity
    • one year ago
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    i mean you have the idea but that's wrong because of the sign

  29. anonymous
    • one year ago
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    3(a)+2-4/(a)

  30. xapproachesinfinity
    • one year ago
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    yes now g(a)-g(a-b)-f(a)=2-3a-(2-3(a-b))+3a+2-4/a

  31. xapproachesinfinity
    • one year ago
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    the difference btw what i just did and what you did is i put those parenthesise before 2-3(a-b) because of the sign that came before it

  32. xapproachesinfinity
    • one year ago
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    if ignored that it would be wrong because the sign has to be distribute to 2-3(a-b)

  33. xapproachesinfinity
    • one year ago
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    so no what we do it open up the parenthesis 2-3a-2+3(a-b)+3a+2-4/a

  34. xapproachesinfinity
    • one year ago
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    we simplify more =2-3a-2+3a-3b+3a+2-4/a =....?

  35. xapproachesinfinity
    • one year ago
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    finish it up

  36. anonymous
    • one year ago
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    oh okay, thanks so much!!

  37. xapproachesinfinity
    • one year ago
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    welcome!

  38. anonymous
    • one year ago
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    so is the final answer 3a-3b+2-4/a

  39. xapproachesinfinity
    • one year ago
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    yeah seems good!

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