kalli
  • kalli
Can someone help me with this problem Solve each equation on the interval [0, 2pi]. 4sin^2-3=0 is the equation
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
kalli
  • kalli
Actually, I think I may have got it but can someone check my answers?
cwrw238
  • cwrw238
what do you get?
cwrw238
  • cwrw238
first what do you get for sin x?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

kalli
  • kalli
4sin^2x - 3 = 0 sin^2x = 3/4 sinx = √3/2 or sinx = -√3/2
cwrw238
  • cwrw238
yes correct
kalli
  • kalli
So would my answer be x= pi/3 or 2pi/3 ?
cwrw238
  • cwrw238
it asks for values in the interval 0 to 2pi and the sine can be negative or positive so there is an angle in each quadrant which satisfies the equation.
kalli
  • kalli
So I should have 4 answers then right?
cwrw238
  • cwrw238
pi/3 and 2pi/3 are 2 answers
cwrw238
  • cwrw238
yes
cwrw238
  • cwrw238
|dw:1433707726572:dw|
cwrw238
  • cwrw238
thers the other 2
cwrw238
  • cwrw238
|dw:1433707815590:dw|
kalli
  • kalli
4pi/3 nd 5pi/3?
cwrw238
  • cwrw238
yes
kalli
  • kalli
Okay thanks so much! Do you mind checking my work for a similar problem as well?
cwrw238
  • cwrw238
ok
kalli
  • kalli
This one is solving on the same interval cos(3x) = -1 ---> 3x = arccos(-1) ---- >3x=pi So x= pi/3
cwrw238
  • cwrw238
3x = pi but it could also = 3pi or 5pi
cwrw238
  • cwrw238
so x = pi/3 , pi, 5pi/3 all of which are in the interval 1 to 2pi
kalli
  • kalli
do i need four answers?
cwrw238
  • cwrw238
no - there are only 3
cwrw238
  • cwrw238
7pi/3 is greater than 2pi
cwrw238
  • cwrw238
you have to be careful with these multiple angles
cwrw238
  • cwrw238
if x must be in the interval 0 to 2pi then 3x is in interval 0 to 6pi
cwrw238
  • cwrw238
ok?
kalli
  • kalli
Ohhh, ok i see

Looking for something else?

Not the answer you are looking for? Search for more explanations.