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anonymous
 one year ago
Deepak bought a new car at the dealership for $25,000. It is estimated that the value of the car will decrease 9% each year. Which exponential function models the value v of the car after t years?
anonymous
 one year ago
Deepak bought a new car at the dealership for $25,000. It is estimated that the value of the car will decrease 9% each year. Which exponential function models the value v of the car after t years?

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Hero
 one year ago
Best ResponseYou've already chosen the best response.0Says "which" meaning, a list of answer choices are available to choose from.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a) v=25,000(1.9)^t b) (same^^) (0.1)^t c) (same^^) (0.91)^t d) (same^^) (1.09)^t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know its either a or d because the 1 comes before the decimal, but i got confused because i don't remember if the 9 has a 0 infront or not

Hero
 one year ago
Best ResponseYou've already chosen the best response.0It's not proper to post answer choices in that manner.

Hero
 one year ago
Best ResponseYou've already chosen the best response.0How do you figure that it's either a or d?

Hero
 one year ago
Best ResponseYou've already chosen the best response.0Explain how you eliminated b or c.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a) v=25,000(1.9)^t b) v=25,000(0.1)^t c) v=25,000(0.91)^t d) v=25,000(1.09)^t my b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i remember that the 1 comes before the decimal

Hero
 one year ago
Best ResponseYou've already chosen the best response.01 comes before the decimal for exponential INCREASE.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh. so when it's not increasing, the 1 comes after the decimal?

Hero
 one year ago
Best ResponseYou've already chosen the best response.0Basically, the only the only value of interest for the general formula \(v = 25000^{kt}\) is the k value. If there's an exponential increase, then \(k = 1 + r\) . If there's an exponential decrease, then \(k = 1  r\) In this case \(r = 0.09\).

Hero
 one year ago
Best ResponseYou've already chosen the best response.0The general formula is \(v = 25000k^t\) sorry.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The formula for exponential growth or decay is: F = P(1 + r)^t where F = future amount P = present amount r = rate of growth or decay t = number of years If r is a rate of growth, r is positive. If r is a rate of decay, r is negative. You have a rate of decay, so r = 9% = 0.09 \(F = 25,000(1  0.9)^t\) \(F = 25,000(0.91)^t\)

Hero
 one year ago
Best ResponseYou've already chosen the best response.0I wrote the k as an exponent. Sorry about that.
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