anonymous
  • anonymous
Deepak bought a new car at the dealership for $25,000. It is estimated that the value of the car will decrease 9% each year. Which exponential function models the value v of the car after t years?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Hero @JackJordan
Hero
  • Hero
Says "which" meaning, a list of answer choices are available to choose from.
anonymous
  • anonymous
a) v=25,000(1.9)^t b) (same^^) (0.1)^t c) (same^^) (0.91)^t d) (same^^) (1.09)^t

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More answers

anonymous
  • anonymous
i know its either a or d because the 1 comes before the decimal, but i got confused because i don't remember if the 9 has a 0 infront or not
Hero
  • Hero
It's not proper to post answer choices in that manner.
Hero
  • Hero
How do you figure that it's either a or d?
Hero
  • Hero
Explain how you eliminated b or c.
anonymous
  • anonymous
a) v=25,000(1.9)^t b) v=25,000(0.1)^t c) v=25,000(0.91)^t d) v=25,000(1.09)^t my b
anonymous
  • anonymous
i remember that the 1 comes before the decimal
Hero
  • Hero
1 comes before the decimal for exponential INCREASE.
anonymous
  • anonymous
oh. so when it's not increasing, the 1 comes after the decimal?
anonymous
  • anonymous
? @Hero
Hero
  • Hero
Basically, the only the only value of interest for the general formula \(v = 25000^{kt}\) is the k value. If there's an exponential increase, then \(k = 1 + r\) . If there's an exponential decrease, then \(k = 1 - r\) In this case \(r = 0.09\).
anonymous
  • anonymous
so it's (0.91)^t
anonymous
  • anonymous
@Hero
anonymous
  • anonymous
@mathstudent55
Hero
  • Hero
The general formula is \(v = 25000k^t\) sorry.
mathstudent55
  • mathstudent55
The formula for exponential growth or decay is: F = P(1 + r)^t where F = future amount P = present amount r = rate of growth or decay t = number of years If r is a rate of growth, r is positive. If r is a rate of decay, r is negative. You have a rate of decay, so r = -9% = -0.09 \(F = 25,000(1 - 0.9)^t\) \(F = 25,000(0.91)^t\)
anonymous
  • anonymous
perfect! thank you!
mathstudent55
  • mathstudent55
Yw
Hero
  • Hero
I wrote the k as an exponent. Sorry about that.

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