anonymous
  • anonymous
What is the solution of log4x − 1032 = 5?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\log_{4x-10} 32=5\]
Nnesha
  • Nnesha
change log to exponential form |dw:1433711587287:dw|
anonymous
  • anonymous
\[4x-10^{32}=5\] like that?

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Nnesha
  • Nnesha
nope let 5 = y so number which is at right side becomes exponent of base
anonymous
  • anonymous
\[4x-10^{5}=\]
anonymous
  • anonymous
=y i meant
Nnesha
  • Nnesha
not equal y y =5 x=32 b =4x-10
Nnesha
  • Nnesha
|dw:1433711954963:dw| it should equal to 32
Nnesha
  • Nnesha
\[(4x-10)^{5}=\color{red}{32}\] and don't forget the parnetheses
Nnesha
  • Nnesha
parentheses
anonymous
  • anonymous
\[(4x-10)^{5}=32\]
anonymous
  • anonymous
okay
anonymous
  • anonymous
so now you solve or what?
Nnesha
  • Nnesha
yes solve that
anonymous
  • anonymous
math is my weak spot soo yea
Nnesha
  • Nnesha
take 5th root both sides to cancel out 5
Nnesha
  • Nnesha
\[\huge\rm \sqrt[5]{(4x-10)^5} = \sqrt[5]{32}\] remember you can convert 5th root to 1/5 exponent and that's how you will cancel 5 exponent
anonymous
  • anonymous
okay so that mean when you cancel out the 5 it will just be 4x-10?
Nnesha
  • Nnesha
yes that's right! same like u take square root to cancel out square now at right side write 32 in terms of 5 base ?^5 = 32 ?
anonymous
  • anonymous
2?
Nnesha
  • Nnesha
yep right so \[\large\sqrt[5]{2^5} = 2^\frac{ 5 }{ 5 }=2\] now solve for x 4x-10 =2 simple algebra :-)
anonymous
  • anonymous
x=3
Nnesha
  • Nnesha
yes that's right :-)

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