## anonymous one year ago What is the solution of log4x − 1032 = 5?

1. anonymous

$\log_{4x-10} 32=5$

2. Nnesha

change log to exponential form |dw:1433711587287:dw|

3. anonymous

$4x-10^{32}=5$ like that?

4. Nnesha

nope let 5 = y so number which is at right side becomes exponent of base

5. anonymous

$4x-10^{5}=$

6. anonymous

=y i meant

7. Nnesha

not equal y y =5 x=32 b =4x-10

8. Nnesha

|dw:1433711954963:dw| it should equal to 32

9. Nnesha

$(4x-10)^{5}=\color{red}{32}$ and don't forget the parnetheses

10. Nnesha

parentheses

11. anonymous

$(4x-10)^{5}=32$

12. anonymous

okay

13. anonymous

so now you solve or what?

14. Nnesha

yes solve that

15. anonymous

math is my weak spot soo yea

16. Nnesha

take 5th root both sides to cancel out 5

17. Nnesha

$\huge\rm \sqrt[5]{(4x-10)^5} = \sqrt[5]{32}$ remember you can convert 5th root to 1/5 exponent and that's how you will cancel 5 exponent

18. anonymous

okay so that mean when you cancel out the 5 it will just be 4x-10?

19. Nnesha

yes that's right! same like u take square root to cancel out square now at right side write 32 in terms of 5 base ?^5 = 32 ?

20. anonymous

2?

21. Nnesha

yep right so $\large\sqrt[5]{2^5} = 2^\frac{ 5 }{ 5 }=2$ now solve for x 4x-10 =2 simple algebra :-)

22. anonymous

x=3

23. Nnesha

yes that's right :-)